No, the moles of an atom and the moles of a molecule are not the same. A mole of any substance contains Avogadro's number of particles, which is approximately 6.022 x 10^23. In the case of an atom, this corresponds to one mole of atoms. In the case of a molecule, this corresponds to one mole of molecules.
To find the mass of 2.25 moles of manganese sulfide (MnS2), you need to calculate the molar mass of MnS2 which is 118.87 g/mol. Then, you can multiply the molar mass by the number of moles to get the mass: 2.25 moles Γ 118.87 g/mol = 267.46 grams. So, the mass of 2.25 moles of manganese sulfide is 267.46 grams.
0.75 moles of any substance is 0.75(6.02x1023) = 4.52x1023 particles. If those particles are CO2 molecules, and each molecule has 2 oxygen atoms, then it's 2(4.52x1023) = 9.04x1023 oxygen atoms.
To find the number of moles of atoms in 7.90 x 10^24 H2SO4 molecules, we first calculate the number of moles of H2SO4 molecules using Avogadro's number (6.022 x 10^23). Then, since there are 7 atoms in one molecule of H2SO4, we multiply the number of moles of H2SO4 molecules by 7 to get the moles of atoms.
The balanced equation for the reaction is: 3Mn3O4 + 8Al -> 9Mn + 4Al2O3. This shows that 3 moles of Mn3O4 produce 9 moles of Mn. Thus, 54.8 moles of Mn3O4 would produce 9 * (54.8/3) = 164.4 moles of Mn atoms.
I must have the same sheet as you as I have the exact same question. Okay, The RFM of Manganese (Mn) is 54.9 The RFM of MnSO4 4H20 is 223 The percentage of Mn in MnSO4 4H2O is 54.9/223 X 100 and that is 24.6 % 0.1 Moles of MnSO4 4H20 is 223/100 X10 = 22.3 24.6 % (percentage of Mn in MnSO4 4H2O) of 22.3 (0.1 Moles of MnSO4 4H2O) is 5.49g Then you do 5.49g/54.9g (RFM of Mn) which is 0.1 Moles of Mn, which is your answer.
No, the moles of an atom and the moles of a molecule are not the same. A mole of any substance contains Avogadro's number of particles, which is approximately 6.022 x 10^23. In the case of an atom, this corresponds to one mole of atoms. In the case of a molecule, this corresponds to one mole of molecules.
To find the mass of 2.25 moles of manganese sulfide (MnS2), you need to calculate the molar mass of MnS2 which is 118.87 g/mol. Then, you can multiply the molar mass by the number of moles to get the mass: 2.25 moles Γ 118.87 g/mol = 267.46 grams. So, the mass of 2.25 moles of manganese sulfide is 267.46 grams.
4,0 moles of the manganese contain 219,75 g.
4,0 moles of the manganese contain 219,75 g.
0.75 moles of any substance is 0.75(6.02x1023) = 4.52x1023 particles. If those particles are CO2 molecules, and each molecule has 2 oxygen atoms, then it's 2(4.52x1023) = 9.04x1023 oxygen atoms.
0.1868 moles
To find the number of moles of atoms in 7.90 x 10^24 H2SO4 molecules, we first calculate the number of moles of H2SO4 molecules using Avogadro's number (6.022 x 10^23). Then, since there are 7 atoms in one molecule of H2SO4, we multiply the number of moles of H2SO4 molecules by 7 to get the moles of atoms.
The balanced equation for the reaction is: 3Mn3O4 + 8Al -> 9Mn + 4Al2O3. This shows that 3 moles of Mn3O4 produce 9 moles of Mn. Thus, 54.8 moles of Mn3O4 would produce 9 * (54.8/3) = 164.4 moles of Mn atoms.
The moles are converted into a number of particles by multiplying 6.02 by 10(with the power of 23)
This is a chemical calculation. there are 3.267 moles in this solution.
Stoichiometry uses coefficient ratios to relate moles of one molecule to moles of another