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1 mole Fe = 55.845g Fe

1 mole Fe = 6.022 x 1023 atoms Fe

23.0g Fe x (1 mole Fe/55.845g Fe) x (6.022 x 1023 atoms Fe/1 mole Fe)

= 2.40 x 1023 atoms Fe

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13y ago
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5mo ago

To determine the number of iron atoms in a 23.0 g iron block, you would first calculate the number of moles of iron using the molar mass of iron (55.85 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of iron to atoms.

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Q: How many iron atoms are present in a 23.0 g iron block?
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