There would be 4.38 moles of fluoride ions in 1.46 moles of aluminum fluoride, as the formula for aluminum fluoride is AlF3 with three fluoride ions per molecule of aluminum fluoride.
There are 3 ions in the formula Al2SO4 (2 aluminum and 1 sulfate), but this formula is wrong. The formula of aluminum sulfate is Al2(SO4)3 which contains 5 ions: 2 aluminum ions and 3 sulfate ions.
The ratio of aluminum ions to sulfur ions in the formula Al2S3 is 2:3. This means that for every 2 aluminum ions, there are 3 sulfur ions present in the compound.
Three chlorine ions are required to bond with one aluminum ion in order to form the compound aluminum chloride. This results in a stable compound with a 1:3 ratio of aluminum to chlorine ions.
Three chlorine ions are required to bond with one aluminum ion to form the compound aluminum chloride. This is because aluminum has a 3+ charge and chlorine has a 1- charge, so the formula for aluminum chloride is AlCl3.
There would be 4.38 moles of fluoride ions in 1.46 moles of aluminum fluoride, as the formula for aluminum fluoride is AlF3 with three fluoride ions per molecule of aluminum fluoride.
Three chloride ions are required to neutralize one aluminum ion. Aluminum has a 3+ charge, while chloride ions have a 1- charge, so three chloride ions are needed to balance the charge.
There are 3 ions in the formula Al2SO4 (2 aluminum and 1 sulfate), but this formula is wrong. The formula of aluminum sulfate is Al2(SO4)3 which contains 5 ions: 2 aluminum ions and 3 sulfate ions.
The ratio of aluminum ions to sulfur ions in the formula Al2S3 is 2:3. This means that for every 2 aluminum ions, there are 3 sulfur ions present in the compound.
Three ions of bromide will combine with one ion of aluminum to form aluminum bromide (AlBr3). This is because aluminum has a +3 charge and bromide ions each have a -1 charge, so three bromide ions are needed to balance the +3 charge of aluminum.
Three chlorine ions are required to bond with one aluminum ion in order to form the compound aluminum chloride. This results in a stable compound with a 1:3 ratio of aluminum to chlorine ions.
Metals with a lower reduction potential than aluminum will be oxidized by aluminum ions. For example, magnesium and zinc are metals that can be oxidized by aluminum ions.
Three chlorine ions are required to bond with one aluminum ion to form the compound aluminum chloride. This is because aluminum has a 3+ charge and chlorine has a 1- charge, so the formula for aluminum chloride is AlCl3.
The formula for aluminum chloride is AlCl3, which consists of aluminum ions (Al3+) and chloride ions (Cl-). In the compound, aluminum donates three electrons to chloride, resulting in the formation of three chloride ions for every aluminum ion.
The compound formed between aluminum ions (Al^3+) and phosphate ions (PO4^3-) is aluminum phosphate, with the formula AlPO4.
Three chloride ions are required to bond with one aluminum ion because aluminum has a +3 charge and chloride has a -1 charge. This results in the formula AlCl3.
There are 6 moles of chloride ions in 3 mol of aluminum chloride, as there are two chloride ions for every one aluminum ion in the formula AlCl3.