To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
You would need to add 18.75g of solid NaOH to the 750g of aqueous solution to obtain a 2.5% NaOH solution by mass.
The molar mass of Ca3(PO4)2 is 310.18 g/mol. From the given data, there is 75% of Ca3(PO4)2 in the sample, so the mass of Ca3(PO4)2 in 1.0 kg of phosphorite is 0.75 kg. This corresponds to approximately 2.41 moles of Ca3(PO4)2 which will produce the same number of moles of P4. This yields about 124.3g of P4 can be produced from the given sample.
To calculate the calories of heat available when the water cools to body temperature, you need to consider the specific heat capacity of water. The specific heat capacity of water is 4.18 J/g°C. By using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change, you can find the answer.
The heat required can be calculated using the formula Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water (4.18 J/g°C), and ΔT is the change in temperature. So, plugging in the values, Q = 750g * 4.18 J/g°C * (75.0°C - 25.0°C) = 187,650 Joules.
When you mix hot and cold water together, the temperature of the resulting mixture will be between the temperatures of the two original waters. This is due to the heat transfer between the hot and cold water until they reach thermal equilibrium.
750g
There are 1000 grams in one kilogram. Therefore, 7500 grams is equal to 7500/1000 = 7.5 kilograms.
750 grams is equal to about 1.65 pounds.
Half of 1.5 kilograms is 0.75 kilograms.
750 grams is approximately 1.65 pounds.
The cost of 750g of potatoes in the UK is (February 2011) about £1.72 in Sainsburys but I believe they're cheaper in ASDA. The imperial equivalent to 750 g (grams) is 1.65 lb (pounds).
750g is 0.75kg, so the ratio of 750g to 1kg is 0.75:1.
1000 grams = 1 kilogram 750 grams = 750/1000 = 3/4 kilogram (as a fraction in its simplest form).
To prepare a 0.400m NaF solution, you need to dissolve 0.400 moles of NaF per liter of solution. With 750g of water, you have about 0.416 L of water. To calculate the grams of NaF needed, multiply the molarity by the volume of solution in liters, then multiply by the molar mass of NaF (sodium fluoride: 41.99 g/mol). So, you would need about 6.991 grams of NaF.
1 kilogram = 1000g 1 quarter = 250g so, 3 quarters = 750g
That is approximately 1 pound , 10.45 ounces
There are 1000g in a kg so 1kg is greater than 750g(.75kg).