The mole of acetic acid (CH3COOH) is 60.05 grams/mol.
The molar mass of acetic acid (CH3COOH) is approximately 60.05 g/mol. Therefore, the mass of one mole of acetic acid is 60.05 grams.
To make a 0.1 M solution of acetic acid in 10 liters of water, you would need 60 grams of acetic acid. This is calculated using the molar mass of acetic acid (60 g/mol) and the formula: Molarity (M) = moles/volume (L).
The molar mass of sulfuric acid (H2SO4) is 98.08 grams/mole. Therefore, there are 98.08 grams in 1 mole of sulfuric acid.
One mole of acetic acid (CH3COOH) has a molar mass of approximately 60.05 grams. This is obtained by adding up the atomic masses of carbon (12.01 g/mol), hydrogen (1.01 g/mol), and oxygen (16.00 g/mol) in the chemical formula CH3COOH.
To determine the number of moles of formic acid in 25 grams of acetic acid, you first need to convert the mass of acetic acid to moles. The molar mass of acetic acid is about 60 g/mol. Then, use the molar ratio between formic acid and acetic acid (1:1) to calculate the number of moles of formic acid.
The mole of acetic acid (CH3COOH) is 60.05 grams/mol.
60
The molar mass of acetic acid (CH3COOH) is approximately 60.05 g/mol. Therefore, the mass of one mole of acetic acid is 60.05 grams.
To make a 0.1 M solution of acetic acid in 10 liters of water, you would need 60 grams of acetic acid. This is calculated using the molar mass of acetic acid (60 g/mol) and the formula: Molarity (M) = moles/volume (L).
The molar mass of sulfuric acid (H2SO4) is 98.08 grams/mole. Therefore, there are 98.08 grams in 1 mole of sulfuric acid.
One mole of acetic acid (CH3COOH) has a molar mass of approximately 60.05 grams. This is obtained by adding up the atomic masses of carbon (12.01 g/mol), hydrogen (1.01 g/mol), and oxygen (16.00 g/mol) in the chemical formula CH3COOH.
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The molar mass of nitric acid (HNO3) is approximately 63 grams per mole.
One mole of acetic acid reacts with one mole of caustic soda (sodium hydroxide) in a neutralization reaction. The molar ratio between acetic acid and caustic soda is 1:1. Therefore, the amount of acetic acid needed to neutralize caustic soda is determined by the molarity of the caustic soda solution being neutralized.
The mass of one mole of a substance is its molecular mass in grams. The molecular mass of acetic acid (CH3COOH) is: 12 + (3 x 1) + 12 + 16 + 16 + 1 = 60, therefore, 1 mole of acetic acid has a mass of 60g. (The numbers used in the calculation are the mass numbers of each element)
This mass is 25,522 g.