answersLogoWhite

0


Best Answer
  • First from atoms to mole (Avogadro's number)

2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Ag

  • and from mole to gram (via molar mass)

3.82 mole * 107.9 g/mole = 412 g Ag

User Avatar

Wiki User

14y ago
This answer is:
User Avatar
More answers
User Avatar

AnswerBot

7mo ago

To find the mass of 2.31024 atoms of silver, you can first calculate the molar mass of silver, which is 107.87 g/mol. Then, divide the number of atoms by Avogadro's number to get the amount in moles, and finally, multiply by the molar mass to get the mass in grams. The mass of 2.31024 atoms of silver would be approximately 4.33 x 10^-23 grams.

This answer is:
User Avatar

User Avatar

Wiki User

16y ago

(2.3 x 1024 atoms Ag) x (1 mole Ag/ 6.022 x 1023 atoms Ag) x (107.0 g Ag/ 1 mole Ag) = 412.1056 g Ag

Convert the atoms Ag to moles of silver. Then convert the moles to grams.

This answer is:
User Avatar

User Avatar

Wiki User

14y ago

There are 6.022*10+23 particles (eg. atoms) in one mole, thus:

2.3*10+24 / 6.022*10+23 = 38.19 = 38 moles Ag-atoms

This answer is:
User Avatar

User Avatar

Wiki User

12y ago

2.3 x 1024 atoms Ag * (1 mol Ag/ 6.022 x 1023 atoms Ag)*(107.9 g Ag/mol Ag) =

412.1 g of Ag

This answer is:
User Avatar

User Avatar

Wiki User

13y ago

2.31024 atoms? this doesnt make sense...

if you mean 2,31024 moles, then m= Ar(Ag) x 2,31024= 249,01 g

This answer is:
User Avatar

User Avatar

Wiki User

12y ago

2.3 X 1024 atoms of silver (1 mole Ag/6.022 X 1023)(107.9 grams/1 mole Ag)

= 412 grams silver

==============

This answer is:
User Avatar

User Avatar

Wiki User

12y ago

1 mole Ag = 107.8682g = 6.022 x 1023 atoms

1.80 x 1023 atoms Ag x (107.8682g)/(6.022 x 1023 atoms) = 32.2g Ag

This answer is:
User Avatar

User Avatar

Wiki User

10y ago

grams = 7.4 x 1024 x (Atomic Mass of silver) / (6.023 x 1023)atomic mass of silver = 107.868

Answer = 1325.2917 grams

This answer is:
User Avatar

User Avatar

Wiki User

8y ago

6,022140857.1023 atoms--------------------------107,8682 g
7,4.1024 atoms-----------------------------------------x

x = 1325,48 g

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many grams are therein 2.31024 atoms of silver?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Earth Science

How many atoms are there in 16.3 grams of sulfur?

There are about 6.02 x 10^23 atoms in 16.3 grams of sulfur, which is Avogadro's number representing one mole of atoms or molecules. This is known as a mole, where one mole of any element contains Avogadro's number of atoms.


How many atoms does 100 grams of gold have?

To find the number of atoms in 100 grams of gold, you would first calculate the number of moles using the molar mass of gold (197 grams/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, approximately 3.01 x 10^23 atoms of gold are present in 100 grams.


How many atoms of Ag are in 1.6grams?

To calculate the number of silver atoms in 1.6 grams of silver (Ag), you first need to determine the molar mass of silver, which is 107.87 g/mol. Then you use Avogadro's number (6.022 x 10^23) to convert the mass to moles, and finally, use the mole to atom conversion to find the number of atoms, which is approximately 9.19 x 10^22 atoms.


7.5 times 10 to the 21 uranium atoms equals how many grams?

To convert uranium atoms to grams, you need to know the molar mass of uranium. Uranium's molar mass is approximately 238.03 g/mol. Therefore, 7.5 x 10^21 uranium atoms would weigh approximately 0.625 grams.


How many atoms in 10 grams of lead?

To find the number of atoms in 10 grams of lead, you would first need to determine the number of moles of lead (using the molar mass of lead) and then use Avogadro's number (6.022 x 10^23 atoms/mol) to calculate the number of atoms. This would be approximately 1.15 x 10^23 atoms in 10 grams of lead.

Related questions

How many grams are there in 2.3x10 to the 24th power atoms of silver?

2.3 X 1024 atoms / 6.022 X 1023 atoms/mole X 107.87 gm/mole of silver = 412 grams


Which equivalence factor set should you use to convert 2.68 x 1011 atoms of silver (Ag) to grams of silver?

To convert atoms to grams, you should use the equivalence factor of 1 mole of silver atoms (Ag) to its molar mass. The molar mass of silver is 107.87 g/mol. Therefore, 1 mole of silver atoms is equal to 107.87 grams. Use this equivalence factor to convert the given number of atoms to grams of silver.


How many atoms of silver in 10.8g?

To find the number of atoms of silver in 10.8g, you need to first calculate the number of moles of silver using its molar mass. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert the moles of silver to number of atoms.


How many silver atoms are there in 3.76g of silver?

To calculate the number of silver atoms in 3.76g of silver, you need to use Avogadro's number and the molar mass of silver. The molar mass of silver is 107.87 g/mol. First, calculate the number of moles in 3.76g of silver. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of silver atoms in that many moles.


How many atoms are in a 0.84 lb sample of silver?

To find the number of atoms in a sample of silver, we first need to convert the mass from pounds to grams. Then we calculate the number of moles of silver using the molar mass of silver. Finally, we use Avogadro's number to convert moles to atoms. The answer would be approximately 2.0 x 10^23 atoms in a 0.84 lb sample of silver.


How many silver atoms are there in 3.70g of silver?

2.09*10^22 This is how you figure it out: 3.74g divided by 107.87(the atomic mass of silver). Then you multiply the number you get by 6.022x10^23 (Avogadros number). And that's your answer.


How many silver atoms are there in 3.68 g of silver?

To calculate the number of silver atoms in 3.68 g of silver, first determine the molar mass of silver (Ag) which is 107.87 g/mol. Next, calculate the number of moles of silver in 3.68 g by dividing the mass by the molar mass. Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of silver to atoms.


How many grams are there in 7.4 x10 to the 24th power atoms of silver?

To convert atoms to grams, you need to know the molar mass of the element. The molar mass of silver is 107.87 g/mol. First, calculate the number of moles in 7.4 x 10^24 atoms by dividing by Avogadro's number (6.022 x 10^23). Then, multiply the number of moles by the molar mass of silver to get the mass in grams.


How many kilograms are therein 4563 grams?

4.563kg


How many ag atoms are there in 0.0001 grams of Ag.Molar mass of Ag is 108 gram per mole?

To find the number of atoms in 0.0001 grams of silver (Ag), first determine the number of moles in 0.0001 grams using the molar mass of Ag (108 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, 0.0001 g of Ag is equal to 6.94 x 10^16 Ag atoms.


What has more atoms 2.88 grams of helium atoms or 16.4 grams of zinc atoms?

2,88 grams of helium have 3,761.1023 atoms; 16,4 grams of zinc have 1,511.1023 atoms.


How many silver atoms are there in 3.88 g of silver?

To find the number of silver atoms in 3.88 g of silver, you can use the formula: Number of atoms = (mass in grams / molar mass) x Avogadro's number The molar mass of silver is 107.87 g/mol, and Avogadro's number is 6.022 x 10^23 mol^-1. Therefore, there are approximately 8.59 x 10^22 silver atoms in 3.88 g of silver.