For this you need the atomic (molecular) mass of O2. Take the number of moles and multiply it by the Atomic Mass. Divide by one mole for units to cancel.
2.047 moles O2 × (32.0 grams) = 65.5 grams O2
To find the grams of O2 in 15 moles, we use the molar mass of O2, which is 32 g/mol. 15 moles x 32 g/mol = 480 grams of O2. Therefore, there are 480 grams of O2 in 15 moles of O2.
There are 192 grams of oxygen in 6 moles of O2.
Two moles of O2 molecules would have a mass of 64 grams (2 moles x 32 grams/mole = 64 grams).
For every 4 moles of KO2 consumed, 3 moles of O2 are produced. Since the molar mass of KO2 is 71.097 g/mol, 323.2 grams of KO2 is approximately 4.55 moles. Therefore, 3/4 * 4.55 = 3.41 moles of O2 are produced. This is equivalent to 6.83 grams of O2.
The balanced chemical equation for the combustion of propane (C3H8) is 1 C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This means 5 moles of O2 are required for every 1 mole of C3H8. Calculate the moles of C3H8 in 51.6 g, then use the mole ratio to find the moles of O2 needed. Finally, convert the moles of O2 to grams.
To find the grams of O2 in 15 moles, we use the molar mass of O2, which is 32 g/mol. 15 moles x 32 g/mol = 480 grams of O2. Therefore, there are 480 grams of O2 in 15 moles of O2.
The answer is 2 moles.
There are 192 grams of oxygen in 6 moles of O2.
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.
0,800 moles of oxygen (O2) is equivalent to 25,6 g.
O2 has a molecular mass of 31.9988 grams per mol. Therefore, 4.5 moles of O2 will equal 144 grams of oxygen.
There are 1.0001 moles.
The number of moles in exactly 64 grams of oxygen (O2) is two.
Two moles of O2 molecules would have a mass of 64 grams (2 moles x 32 grams/mole = 64 grams).
The mass of 3.2 moles O2? The atoms in 3.2 moles O2 Could be other things, I guess, but I will do these two. 3.2 moles O2 (32 grams/1 mole O2) = 102.4 grams of gaseous oxygen -------------------------------------------- 3.2 mole O2 (6.022 X 1023/1 mole O2) = 1.9 X 1024 atoms of gaseous oxygen --------------------------------------------------
From the balanced chemical equation, 4 moles of KOH produce 1 mole of O2. Given that there are 6.21 moles of KOH, we can set up a ratio: (6.21 moles KOH) x (1 mole O2 / 4 moles KOH) = 1.5525 moles O2. Finally, using molar mass of oxygen (O2) which is 32 g/mol, we find that 1.5525 moles of O2 is equal to 49.68 grams of O2.