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1 mole of NaHCO3

Na = 1 * 22.99 g = 22.99 g

H = 1 * 1.01 g = 1.01 g

C = 1 * 12.01 g = 12.01 g

O = 3 * 16.00 g = 48.00 g

Total = 84.01 g

There are 84.01 grams in one mole of NaHCO3.

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14y ago
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5mo ago

The molar mass of NaHCO3 is approximately 84 grams per mole. This means that 1 mole of NaHCO3 contains 84 grams of the compound.

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15y ago

There are 5 atoms in one molecule of NaCO3 (Na → 1 atom + C → 1 atom + O3 → 3 atoms = 5 atoms).

In a mole (6.022 x 1023) of NaCO3 there are 3.01 x 1024 atoms.

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13y ago

.11905 moles

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Q: How many grams are in 1 mol nahco3?
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To determine the number of moles in 86.6 grams of sodium bicarbonate (NaHCO3), divide the given mass by the molar mass of NaHCO3. The molar mass of NaHCO3 is approximately 84 grams/mol. Therefore, 86.6 grams of NaHCO3 is equal to approximately 1.03 moles.


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To calculate the solute mass of NaHCO3, you first need to determine the molar mass of NaHCO3, which is 84.01 g/mol. Then, you can use the formula: mass = moles x molar mass. Plugging in the values, the solute mass of NaHCO3 would be 0.025 mol x 84.01 g/mol = 2.10 grams.


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