To determine the number of moles in 86.6 grams of sodium bicarbonate (NaHCO3), divide the given mass by the molar mass of NaHCO3. The molar mass of NaHCO3 is approximately 84 grams/mol. Therefore, 86.6 grams of NaHCO3 is equal to approximately 1.03 moles.
To find the moles of NaHCO3 in a 3.00 g sample, first calculate the molar mass of NaHCO3 (84.01 g/mol). Then, divide the mass of the sample by the molar mass to obtain the moles of NaHCO3. For this sample, 3.00 g / 84.01 g/mol ≈ 0.036 moles of NaHCO3 are present.
To convert grams to moles, you need to divide the given mass by the molar mass of the substance. The molar mass of baking soda (NaHCO3) is 84.01 g/mol. So, 2.00 grams of baking soda is equal to 0.0238 moles.
To have 1 mole of H2O, you would need to weigh out approximately 18 grams of water (H2O). This is because 1 mole of water molecules (H2O) has a molar mass of about 18 grams/mol (2 grams/mol for hydrogen x 2 atoms + 16 grams/mol for oxygen).
The molar mass of carbon is 12.01 g/mol. Therefore, 1.00 mol of carbon would contain 12.01 grams of carbon.
To determine the number of moles in 86.6 grams of sodium bicarbonate (NaHCO3), divide the given mass by the molar mass of NaHCO3. The molar mass of NaHCO3 is approximately 84 grams/mol. Therefore, 86.6 grams of NaHCO3 is equal to approximately 1.03 moles.
To calculate the solute mass of NaHCO3, you first need to determine the molar mass of NaHCO3, which is 84.01 g/mol. Then, you can use the formula: mass = moles x molar mass. Plugging in the values, the solute mass of NaHCO3 would be 0.025 mol x 84.01 g/mol = 2.10 grams.
To find the moles of NaHCO3 in a 3.00 g sample, first calculate the molar mass of NaHCO3 (84.01 g/mol). Then, divide the mass of the sample by the molar mass to obtain the moles of NaHCO3. For this sample, 3.00 g / 84.01 g/mol ≈ 0.036 moles of NaHCO3 are present.
To neutralize 150 mL of 0.44 M HCl, you would need an equal number of moles of NaHCO3. First, calculate the number of moles of HCl (mol = Molarity x Volume) used. Then, since 1 mol of NaHCO3 neutralizes 1 mol of HCl, you would need the same number of moles of NaHCO3. From that, you can calculate the mass of NaHCO3 needed using its molar mass.
Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3
To convert grams to moles, you need to divide the given mass by the molar mass of the substance. The molar mass of baking soda (NaHCO3) is 84.01 g/mol. So, 2.00 grams of baking soda is equal to 0.0238 moles.
To have 1 mole of H2O, you would need to weigh out approximately 18 grams of water (H2O). This is because 1 mole of water molecules (H2O) has a molar mass of about 18 grams/mol (2 grams/mol for hydrogen x 2 atoms + 16 grams/mol for oxygen).
I just had this question on my chem homework so I'll see if I can help. First thing you need to do is balance the equation. The balanced equation should look like this: 2NaHCO3 -----> Na2CO3 + H2O +CO2 With that out of the way we can start converting. The Molar Mass of NaHCO3 is 84 (or close to it, depending on how you round your decimals) So we do 5g NaHCO3/ 84g NaHCO3. That should give you about 0.059. Next we do 0.059/2mol NaHCO3, because we know from the balanced equation that we have a 2:1:1:1 ratio. That should give you about 0.0295. Now we find the Molar Mass of CO2, which is around 44. Lastly, we go 0.0295x44 and that should give us the answer. I got 1.3g of CO2 as my answer. I hope I was able to be of some use. :)
8 mol x (4 mol / 2 mol) x 133.5 g / 1 mol = 2136 grams
To convert grams to moles, divide the mass in grams by the molar mass of the substance. The molar mass of water is approximately 18 g/mol (1 g/mol for hydrogen and 16 g/mol for oxygen). So, 5.8 grams of water in 1 liter would be approximately 0.32 moles (5.8 g / 18 g/mol).
The molar mass of carbon is 12.01 g/mol. Therefore, 1.00 mol of carbon would contain 12.01 grams of carbon.
4.563 grams are in 1 mole of Strontium Nitrate.