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There are 3.01 x 10^24 formula units of CaCl2 in 2.50 moles. This can be calculated using Avogadro's number (6.022 x 10^23) and the formula units present in one mole of CaCl2 (3).

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Q: How many formula units are present in 2.50 moles of CaCl2?
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How many moles of CaCl2 contain 1.26x1024 formula units of CaCl2?

To calculate the number of moles, first find the molar mass of CaCl2 (40.08 g/mol for Ca + 2 * 35.45 g/mol for Cl). Then divide the given number of formula units by Avogadro's number (6.022 x 10^23 formula units/mol) to get the number of moles.


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To find the number of moles of CaCl2 in 2.00x10^24 formula units, you need to first determine the molar mass of CaCl2, which is 110.98 g/mol. Then, divide the number of formula units by Avogadro's number (6.022x10^23) to convert to moles. This gives you approximately 3.32 moles of CaCl2.


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To calculate the number of moles of CaCl2, you first need to find the molar mass of CaCl2, which is 110.98 g/mol. Then, you divide the given number of formula units (1.261024) by Avogadro's number to convert it to moles. So, the answer would be approximately 1.14 moles of CaCl2.


How many moles of CaCl2 contains 1.26 times 10 24 formula units CaCI2?

The answer is 2,09 moles.


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To find the number of moles of CaCl2, first calculate the molar mass of CaCl2: Ca: 40.08 g/mol Cl: 35.45 g/mol (x2 since there are two Cl atoms) Total molar mass: 40.08 + 35.45(2) = 110.98 g/mol Next, calculate the number of moles: 2.41 x 10^24 formula units / Avogadro's number (6.022 x 10^23) = 4 moles of CaCl2.


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