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How many moles of CaCl2 are in 2.00 1024 formula units?
To find the number of moles of CaCl2 in 2.00x10^24 formula units, you need to first determine the molar mass of CaCl2, which is 110.98 g/mol. Then, divide the number of formula units by Avogadro's number (6.022x10^23) to convert to moles. This gives you approximately 3.32 moles of CaCl2.
How many formula units of AgNO3 are present in 147g of this compound?
To determine the number of formula units of AgNO3 in 147g of the compound, you first need to calculate the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. Next, divide the given mass (147g) by the molar mass to find the number of moles present in the sample. Finally, use Avogadro's number (6.022 x 10^23) to convert moles to formula units.
How many formula units of LiCl are equal to .648 moles?
42.394 grams.
How many moles of CaCl2 are in 250 ml of CaCl2 solution?
To determine the number of moles of CaCl2 in a solution, you need to know the concentration of the solution in mol/L. Without this information, it is not possible to calculate the number of moles of CaCl2 in the given volume of 250 ml.
What is the mass of 5.55 1022 formula units of calcium chloride CaCl2?
The molar mass of CaCl2 is 110.98 g/mol. To find the mass of 5.55 x 10^22 formula units, you would multiply the molar mass by the number of formula units. This gives a mass of approximately 6.16 x 10^24 grams.
How many moles of CaCl2 are in 2.00 1024 formula units?
To find the number of moles of CaCl2 in 2.00x10^24 formula units, you need to first determine the molar mass of CaCl2, which is 110.98 g/mol. Then, divide the number of formula units by Avogadro's number (6.022x10^23) to convert to moles. This gives you approximately 3.32 moles of CaCl2.
How many moles of CaCl2 contain 1.26x1024 formula units of CaCl2?
Oh, dude, let me break it down for you. So, 1 mole of CaCl2 contains 6.022 x 10^23 formula units, right? And you've got 1.26 x 10^24 formula units of CaCl2. So, you just divide 1.26 x 10^24 by 6.022 x 10^23 to get the number of moles. Easy peasy, lemon squeezy!
How many moles of CaCl2 contain 1.261024 formula units of CaCl2?
To calculate the number of moles of CaCl2, you first need to find the molar mass of CaCl2, which is 110.98 g/mol. Then, you divide the given number of formula units (1.261024) by Avogadro's number to convert it to moles. So, the answer would be approximately 1.14 moles of CaCl2.
How many moles of CaCl2 contains 1.26 times 10 24 formula units CaCI2?
The answer is 2,09 moles.
How many moles of CaCl2 does 2.41 x 10 to the 24th formula units represent?
To find the number of moles of CaCl2, first calculate the molar mass of CaCl2: Ca: 40.08 g/mol Cl: 35.45 g/mol (x2 since there are two Cl atoms) Total molar mass: 40.08 + 35.45(2) = 110.98 g/mol Next, calculate the number of moles: 2.41 x 10^24 formula units / Avogadro's number (6.022 x 10^23) = 4 moles of CaCl2.
7.5 grams of CaCl2 is how many moles?
To find the number of moles of CaCl2, you need to use its molar mass. The molar mass of CaCl2 is approximately 110.98 g/mol. Dividing 7.5 g by the molar mass gives you approximately 0.067 moles of CaCl2.
Determine the number of formula units that are in 0.688 moles of AgNO3?
0.688 moles*6.02x1023=4.14x1023 Formula units
How many formula units of sodium acetate are in 0.87 moles of sodium acetate?
There are 5.25 x 10^22 formula units in 0.87 moles of sodium acetate. This is determined by multiplying the Avogadro's number (6.022 x 10^23 formula units/mole) by the number of moles.
What is the number of formula units that are in 5.68 moles of magnesium oxide?
To find the number of formula units of magnesium oxide in 5.68 moles, you first need to determine the formula of magnesium oxide (MgO). Then use Avogadro's number (6.022 x 10^23) to convert moles to formula units. So, in 5.68 moles of MgO, there are approximately 3.43 x 10^24 formula units.
How many formula units of salt make up 10 moles?
10 formula units
How many formula units of AgNO3 are present in 147g of this compound?
To determine the number of formula units of AgNO3 in 147g of the compound, you first need to calculate the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. Next, divide the given mass (147g) by the molar mass to find the number of moles present in the sample. Finally, use Avogadro's number (6.022 x 10^23) to convert moles to formula units.
How many moles are equivalent to 3.6x1024 formula units of MgBr2?
The answer is 5,978 moles.
