0
MgF2 has a molecular weight of 24+19*2 = 62g. Thus, 31 grams of MgF2 represent .5mol. There are 6.022*10^23 particles per mole. Since MgF2 has three atoms in it, we can find the number of atoms by the following:
(.5 mol)(6.022*10^23 particles/mol)(3 atoms in MgF2) = ...
Enjoy your free high school chemistry answer!
To determine the number of atoms in 31 grams of magnesium fluoride, you need to first calculate the number of moles of magnesium fluoride using its molar mass. The molar mass of magnesium fluoride is 62.301 g/mol. Dividing 31 grams by the molar mass gives approximately 0.498 moles. Since magnesium fluoride has the chemical formula MgF2, each molecule contains 3 atoms (1 magnesium and 2 fluorine). So 0.498 moles of MgF2 contain approximately 2.986 x 10^23 atoms.
Add your answer:
Earn +20 pts
How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
To convert moles to grams, you need to use the molar mass of magnesium fluoride, which is 62.301 grams/mol. Thus, 4.78 moles of magnesium fluoride would be 4.78 moles * 62.301 grams/mol = 298.06 grams of magnesium fluoride.
How many fluoride atoms are in a tube of toothpaste?
The number of fluoride atoms in a tube of toothpaste can vary depending on the brand and formulation. However, a standard 4 oz tube of toothpaste typically contains around 0.24 grams of fluoride, which is roughly equal to 1.7 x 10^19 fluoride atoms.
How many grams of magnesium would be required to produce 4.00 grams of magnesium oxide?
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
How much fluorine in grams was formed when the mass ratio of sodium to fluorine in sodium fluoride is 1 to 21 to 1 A sample of sodium fluoride produced 27point7 grams of sodium upon decomposition?
To find the mass of fluorine produced, first calculate the mass of sodium fluoride: 27.7 grams of sodium / (1 part sodium / 1 part sodium fluoride) = 27.7 grams of sodium fluoride Now, since the ratio of sodium to fluorine in sodium fluoride is 1:2 (1 part sodium to 2 parts fluorine), the mass of fluorine is 27.7 grams / 2 = 13.85 grams.
How many grams in magnesium?
The atomic mass of magnesium (Mg) is approximately 24.305 grams per mole.
How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
To convert moles to grams, you need to use the molar mass of magnesium fluoride, which is 62.301 grams/mol. Thus, 4.78 moles of magnesium fluoride would be 4.78 moles * 62.301 grams/mol = 298.06 grams of magnesium fluoride.
How many grams of magnesium fluoride would you produce if you added 24 grams of magnesium to 38 grams of fluorine?
Theoretically the mass is 62,3018 g.
How many atoms are present in 7.92g of calcium fluoride?
Calculate the number of moles of calcium fluoride by dividing the mass by its molar mass. The molar mass of calcium fluoride (CaF2) is 78.08 g/mol. Then, multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of atoms present in 7.92g of calcium fluoride.
What is the formula for magnesium and fluorine?
The chemical formula for magnesium fluoride is MgF2.
How many fluoride atoms are in a tube of toothpaste?
The number of fluoride atoms in a tube of toothpaste can vary depending on the brand and formulation. However, a standard 4 oz tube of toothpaste typically contains around 0.24 grams of fluoride, which is roughly equal to 1.7 x 10^19 fluoride atoms.
What is the number of magnesium atoms that equal a mass of 24.31?
The molar mass of magnesium is approximately 24.31 g/mol. Therefore, 24.31 g of magnesium would contain Avogadro's number of magnesium atoms, which is approximately 6.022 x 10^23 atoms.
How many grams of sodium contain the same numberof atom as 15grams of magnesium?
Let us find Magnesium atoms first. 15 grams magnesium (1 mole Mg/24.31 grams)(6.022 X 10^23/1 mole Mg) = 3.72 X 10^23 atoms magnesium Now take this an drive to grams sodium 3.72 X 10^23 atoms (1 mole Na/6.022 X 10^23)(22.99 grams/1 mole Na) = 14 grams of sodium ----------------------------
What number of atoms is present in 8 gm of magnesium?
To find the number of atoms in 8 grams of magnesium, you need to first calculate the number of moles of magnesium using its molar mass (24.305 g/mol). Then, use Avogadro's number (6.022 x 10^23) to convert moles to atoms. This calculation would result in approximately 3.28 x 10^23 atoms of magnesium in 8 grams.
How many atoms in 36g of magnesium?
The molar mass of magnesium is approximately 24.3 g/mol. Therefore, 36 g of magnesium is equal to 1.48 moles. Since 1 mole of magnesium contains 6.022 x 10^23 atoms, 1.48 moles would contain approximately 8.9 x 10^23 atoms.
How many hydrogen atoms are present in 3.65 grams of water?
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.
How many grams of magnesium would be required to produce 4.00 grams of magnesium oxide?
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
There are 6 grams of magnesium and 4 grams of oxygen if 8 grams of magnesium oxide is produced?
2
