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3.14 g Cu = # atoms

Take the known mass of copper multiply it by Avogadro number and divided by the atomic weight.

Atomic weight of copper:

63.5 g

3.14 g Cu (6.02 × 1023 atoms) / (63.5 grams) = 2.98 × 1022 atoms of Copper

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15y ago
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15y ago

For this problem, the Atomic Mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.

3.14 grams Cu / (63.5 grams) × (6.02 × 1023 atoms) = 2.98 × 1022 atoms

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AnswerBot

7mo ago

There are approximately 4.70 x 10^22 atoms in 3.14 g of copper (Cu) based on the molar mass of copper (63.55 g/mol) and Avogadro's number (6.022 x 10^23 atoms/mol).

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13y ago

[ 10.4333 (g Cu) / 63.55 (g/mol Cu) ] * 6.022*10+23 (atoms/mol) = 98.87*10+21 atoms

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7y ago

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4y ago

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Q: How many atoms are present in 3.14g of Cu?
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How many Cu atoms are present in 85mol?

To calculate the number of Cu atoms in 85 mol, you need to use Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol. So, for 85 mol of Cu, the number of Cu atoms would be 85 mol x 6.022 x 10^23 atoms/mol = 5.12 x 10^25 Cu atoms.


How may atoms of oxygen are present in Cu(NO3)2?

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There are 5 atoms in one molecule of Cu(OH)2, comprising one copper (Cu) atom, two oxygen (O) atoms, and two hydrogen (H) atoms.


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How many oxygen atoms are present in a 14.0 g sample of Cu(NO3)2?

There are 6 oxygen atoms present in one formula unit of Cu(NO3)2. To find the number of oxygen atoms in a 14.0 g sample, you would need to calculate the number of formula units in 14.0 g of Cu(NO3)2. Then, multiply that by 6 to find the total number of oxygen atoms in the sample.


How many oxygen atoms are there in a molecule of copper nitrate?

The compound copper nitrate has Cu(NO3)2 for a chemical formula. In that formula, we see that there is an NO3 radical present, and that there are 3 atoms of oxygen in that radical (the sub 3 after the O). But there are 2 of those NO3 radicals (the sub 2 outside of the parens) present in this compound. That means that there are 3 x 2 oxygen atoms in a molecule of copper nitrate, or 6 atoms of oxygen in Cu(NO3)2.


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Divide that number of atoms by 6.02x10^23 atoms/mole


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1 w


How many atoms are in CU(NO3)2?

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