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0.44 mole Pb (6.022 X 10^23/1 mole Pb)

= 2.6 X 10^23 atoms of lead

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βˆ™ 13y ago
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βˆ™ 5mo ago

There are 2.652 x 10^22 atoms in 0.44 moles of lead (Pb). This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles (0.44).

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Q: How many atoms are in point 44 mole of Pb?
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