To find the number of atoms in 175 g of calcium, we need to first calculate the number of moles of calcium using its atomic mass (40.08 g/mol). Then, we can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to get the total number of atoms in 175 g of calcium.
The mass of one gold atom is approximately 197 atomic mass units. Therefore, the mass of 175 gold atoms would be approximately 34,475 atomic mass units.
To find the molar mass of CHCl3, you would calculate the sum of the atomic masses of carbon, hydrogen, and three chlorine atoms. The atomic masses are: carbon (C) = 12.01 g/mol, hydrogen (H) = 1.01 g/mol, and chlorine (Cl) = 35.45 g/mol. Therefore, the molar mass of CHCl3 is 12.01 (C) + 1.01 (H) + 3*(35.45) (3 Cl) = 119.37 g/mol.
The molar mass of chloroform (CHCl3) is approximately 119.38 g/mol.
There are approximately 4.65 x 10^22 atoms in 0.0077 mol of carbon.
To find the number of atoms in 175 g of calcium, we need to first calculate the number of moles of calcium using its atomic mass (40.08 g/mol). Then, we can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to get the total number of atoms in 175 g of calcium.
The mass of one gold atom is approximately 197 atomic mass units. Therefore, the mass of 175 gold atoms would be approximately 34,475 atomic mass units.
The molecular mass of CHCl3 is 119.37 g/mol. Chlorine has a molar mass of 35.45 g/mol. So the percentage by mass of chlorine in CHCl3 is (3 * 35.45) / 119.37 * 100 ≈ 89.0%.
To find the molar mass of CHCl3, you would calculate the sum of the atomic masses of carbon, hydrogen, and three chlorine atoms. The atomic masses are: carbon (C) = 12.01 g/mol, hydrogen (H) = 1.01 g/mol, and chlorine (Cl) = 35.45 g/mol. Therefore, the molar mass of CHCl3 is 12.01 (C) + 1.01 (H) + 3*(35.45) (3 Cl) = 119.37 g/mol.
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
The molar mass of chloroform (CHCl3) is approximately 119.38 g/mol.
To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.
There are approximately 4.65 x 10^22 atoms in 0.0077 mol of carbon.
The answer is 18,061.1023 atoms.
48,177 134 32.1023 atoms
There are 0.45 mol of BaSO4. In one mole of BaSO4, there is one sulfur atom. Therefore, there are 0.45 mol of sulfur atoms in 0.45 mol of BaSO4.
Avagadro's number = 6.022 × 1023 atoms/mol0.5 mol × (6.022 × 1023) atoms/mol = 3.011 ×1023 atoms