0
A mole (more properly called a "gram Atomic Mass") of K contains Avogadro's Number of atoms. Therefore, 0.0384 moles contains 0.0384 X Avogadro's Number or about 2.31 X 1022 atoms, to the justified number of significant digits.
Still curious? Ask our experts.
Chat with our AI personalities
Beau
Blake
Devin
Add your answer:
Earn +20 pts
How many atoms are in 0.0671 mol K?
There are 4.05 x 10^22 atoms in 0.0671 mol of potassium (K). This is calculated by multiplying the Avogadro's number (6.022 x 10^23) by the number of moles.
How many moles are in 3.3 moles of K2S?
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
What is the concentration of K in 0.15M of K2S?
If you have 2 moles of K+ for every mole of K2S and Molarity (M) is Moles per Liter. Then you know that you have .30 M of K2S. The way that you do that is setting up a series of conversion factors like so:(.15moles k2s/liter) x (2 moles of K/ 1 mole of K2S) = .30 moles k/ liter.The moles of K2S cancel out and you are left with moles of K per liter.
How many moles of cations are in 1.30 mol of rmK 2 rmSO 4?
There are 2 moles of potassium cations (K+) in 1 mole of K2SO4, so in 1.30 moles of K2SO4 there would be 2.60 moles of potassium cations.
How many atoms are in 131.97 liters of water vapor at STP?
At STP (standard temperature and pressure), one mole of any gas occupies 22.4 liters. So 131.97 liters of water vapor is 131.97/22.4 = 5.89 moles. Since water has two hydrogen atoms and one oxygen atom per molecule, each mole of water contains 2 + 1 = 3 atoms. Therefore, 5.89 moles contain 5.89 x 3 = 17.67 moles of atoms.
