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A mole (more properly called a "gram Atomic Mass") of K contains Avogadro's Number of atoms. Therefore, 0.0384 moles contains 0.0384 X Avogadro's Number or about 2.31 X 1022 atoms, to the justified number of significant digits.

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There are approximately 2.32 x 10^22 atoms in 0.0384 moles of potassium (K). This can be calculated using Avogadro's number, which states that there are 6.022 x 10^23 atoms in one mole of an element.

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Q: How many atoms are in 0.0384 moles K?
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How many atoms are in 0.3 moles of potassium?

0.3 moles K (6.022 X 10^23/1mol K) = 1.8 X 10^23 atoms of K


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There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K. Therefore, 3.5 moles * 6.022E23 atoms/1 mole= 2.107E24


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How many moles are in 3.3 moles of K2S?

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