A mole (more properly called a "gram Atomic Mass") of K contains Avogadro's Number of atoms. Therefore, 0.0384 moles contains 0.0384 X Avogadro's Number or about 2.31 X 1022 atoms, to the justified number of significant digits.
There are 4.05 x 10^22 atoms in 0.0671 mol of potassium (K). This is calculated by multiplying the Avogadro's number (6.022 x 10^23) by the number of moles.
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
If you have 2 moles of K+ for every mole of K2S and Molarity (M) is Moles per Liter. Then you know that you have .30 M of K2S. The way that you do that is setting up a series of conversion factors like so:(.15moles k2s/liter) x (2 moles of K/ 1 mole of K2S) = .30 moles k/ liter.The moles of K2S cancel out and you are left with moles of K per liter.
At STP (standard temperature and pressure), one mole of any gas occupies 22.4 liters. So 131.97 liters of water vapor is 131.97/22.4 = 5.89 moles. Since water has two hydrogen atoms and one oxygen atom per molecule, each mole of water contains 2 + 1 = 3 atoms. Therefore, 5.89 moles contain 5.89 x 3 = 17.67 moles of atoms.
There are 2 moles of potassium cations (K+) in 1 mole of K2SO4, so in 1.30 moles of K2SO4 there would be 2.60 moles of potassium cations.
0.3 moles K (6.022 X 10^23/1mol K) = 1.8 X 10^23 atoms of K
0.0384 moles K x 6.02x10^23 atoms/mole = 2.31x10^22 atoms
There are 4.05 x 10^22 atoms in 0.0671 mol of potassium (K). This is calculated by multiplying the Avogadro's number (6.022 x 10^23) by the number of moles.
There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K. Therefore, 3.5 moles * 6.022E23 atoms/1 mole= 2.107E24
There are 1 mole of atoms in 6.022 x 10^23 atoms (Avogadro's number). Therefore, to find the number of moles in 6.81 x 10^24 atoms, you would divide the given number of atoms by Avogadro's number: 6.81 x 10^24 atoms / 6.022 x 10^23 atoms/mole = 11.33 moles.
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
1 fomula unit of KOH has 3 atoms: 1 potassium (K), 1 oxygen (O), and 1 hydrogen (H).
To find the number of K atoms in KCl, we first calculate the molar mass of KCl: 39.10 (K) + 35.45 (Cl) = 74.55 g/mol. Next, we determine the number of moles of KCl in 2.77g: 2.77g / 74.55 g/mol = 0.0371 mol. Since there is 1 K atom in 1 KCl molecule, the number of K atoms in 2.77g of KCl is the same as the number of moles of KCl, which is 0.0371 mol.
To find the mass of the sample, you would first determine the molar mass of potassium (approximately 39.1 g/mol). Then, you would multiply the number of atoms by the molar mass to find the total mass. In this case, you would calculate (1.72 x 10^23 atoms) x (39.1 g/mol) = mass of the sample.
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
If you have 2 moles of K+ for every mole of K2S and Molarity (M) is Moles per Liter. Then you know that you have .30 M of K2S. The way that you do that is setting up a series of conversion factors like so:(.15moles k2s/liter) x (2 moles of K/ 1 mole of K2S) = .30 moles k/ liter.The moles of K2S cancel out and you are left with moles of K per liter.
Okay, a mole of potassium perchlorate contains 6.02x1023 formula units of potassium perchlorate, but you're asking about individual atoms. So, let's look at the formula: KClO3. That's 1 potassium, 1 chlorine, and 3 oxygens, for a total of 5 atoms per formula unit. Now, multiple 5 by Avogadro's number above, to get 30.1x1023, which simplifies to 3.01x1024 atoms.