To find the amount of hydrogen needed to produce water, we need to consider the chemical formula of water, which is H2O. This indicates that there are 2 grams of hydrogen for every 18 grams of water. Therefore, 30.0 grams of water would require 3.33 grams of hydrogen (30.0 grams * 2 grams/18 grams).
When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.
To find the number of moles in 180 grams of water, divide the mass by the molar mass of water. The molar mass of water is approximately 18 g/mol (2*1 (hydrogen) + 16 (oxygen)). So, 180g Γ· 18 g/mol = 10 moles of water.
45 g water are obtained.
At standard conditions, 1 mole of hydrogen reacts with 0.5 moles of oxygen to form 1 mole of water. Therefore, to form 5 moles of water, you will need 5 moles of hydrogen and 2.5 moles of oxygen. The molar mass of water is approximately 18 g/mol, so 5 moles of water would weigh 90 grams.
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.
75 grams water is equal to 4,166 moles.
To find the amount of hydrogen needed to produce water, we need to consider the chemical formula of water, which is H2O. This indicates that there are 2 grams of hydrogen for every 18 grams of water. Therefore, 30.0 grams of water would require 3.33 grams of hydrogen (30.0 grams * 2 grams/18 grams).
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When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.
To find the number of moles in 180 grams of water, divide the mass by the molar mass of water. The molar mass of water is approximately 18 g/mol (2*1 (hydrogen) + 16 (oxygen)). So, 180g Γ· 18 g/mol = 10 moles of water.
45 g water are obtained.
At standard conditions, 1 mole of hydrogen reacts with 0.5 moles of oxygen to form 1 mole of water. Therefore, to form 5 moles of water, you will need 5 moles of hydrogen and 2.5 moles of oxygen. The molar mass of water is approximately 18 g/mol, so 5 moles of water would weigh 90 grams.
To make 36 grams of water (H2O), you would need 2 moles of hydrogen. This is because the molecular formula of water is H2O, meaning each molecule of water contains 2 atoms of hydrogen.
The balanced chemical equation for the reaction of hydrogen gas and oxygen gas to form water is 2Hβ + Oβ β 2HβO. This means that 2 moles of water are produced for every 1 mole of oxygen gas. Therefore, 4.4 moles of water are produced from the reaction of 2.2 moles of oxygen gas. To convert moles of water to grams, you would need to use the molar mass of water, which is approximately 18 grams/mol. So, 4.4 moles of water would weigh approximately 79.2 grams (4.4 moles x 18 grams/mol).
There are 1.5 moles of water molecules in a 27 gram sample of water. This is calculated by dividing the mass of the sample (27 grams) by the molar mass of water (18 grams/mol).
In 0.5 g of water (H2O), there are approximately 3.34 x 10^22 atoms of hydrogen present. This is calculated using Avogadro's number and the molecular weight of water.