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7.596/42=0.18085mol 0.1808 x 6.022 x 10^23=1.09 x 10 ^23

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To find the number of CaH2 formula units in 7.596 g of CaH2, we first calculate the molar mass of CaH2, which is 42.08 g/mol. Then, we use this molar mass to convert the mass to moles (7.596 g / 42.08 g/mol = 0.1804 mol). Finally, we use Avogadro's number to convert moles to formula units (0.1804 mol * 6.022 x 10^23 formula units/mol = 1.09 x 10^23 formula units).

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Q: How many Cah2 formula units are present in 7.596 g of CaH2?
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Related questions

What are the chemical formula of cah2?

The chemical formula for calcium hydride (CaH2) consists of one calcium atom bonded to two hydrogen atoms.


Formula for calcium hydride?

The chemical formula for calcium hydride is CaH2. It is a white crystalline solid that reacts with water to produce hydrogen gas and calcium hydroxide.


What is the chemical formula for calcium and hydrogen?

The chemical formula for Calcium Hydride is CaH2


The formula CaH2 represents what compound?

calcium hydrate


What is the chemical formula for calcium hydrogen phosphide?

The chemical formula for calcium hydrogen phosphide is CaH4P2.


How do you do the crossover method for calcium hydride?

To do the crossover method for calcium hydride (CaH2), you simply swap the charges of the elements to determine the formula. Since calcium (Ca) is a +2 cation and hydride (H) is a -1 anion, the formula becomes CaH2.


What is the formula for calcium hydrogen sulfide?

The formula for calcium hydrogen sulfide is Ca(HS)2. It consists of one calcium ion (Ca2+) and two hydrogen sulfide ions (HS-).


Calculate the total number of atoms in 15 g CaH2?

To calculate the total number of atoms in 15 g of CaH2, we first need to find the number of moles of CaH2 using its molar mass. The molar mass of CaH2 is 42.08 g/mol. Therefore, 15 g of CaH2 is equal to 15/42.08 = 0.356 moles of CaH2. Since each mole of CaH2 contains 3 atoms (1 calcium atom and 2 hydrogen atoms), there are 0.356 * 3 = 1.068 moles of atoms in 15 g of CaH2. This is equivalent to 1.068 * 6.022 x 10^23 = 6.44 x 10^23 atoms.


How many moles of hydrogen will be produced if 0.44 mol of cah2 reacts according to the following equation cah2 plus 2 h2o -- caoh2 plus 2 h2?

One mole of CaH2 produces 2 moles of H2. Therefore, 0.44 mol of CaH2 will produce 2 * 0.44 mol = 0.88 mol of H2.


What is the strength of CaH2 base?

Calcium hydride (CaH2) is considered a strong base, as it is a source of hydroxide ions when it reacts with water. It is a powerful reducing agent and can react violently with water to produce hydrogen gas and calcium hydroxide. CaH2 is commonly used to remove trace water from solvents and gases in laboratories.


How many grams of calcium hydride are needed to form 8.800g of hydrogen?

The molar mass of calcium hydride (CaH2) is 42.09 g/mol. To calculate the moles of CaH2 needed to form 8.800 g of hydrogen, divide the given mass of hydrogen by the molar mass of hydrogen (2.016 g/mol) and then multiply by 2 to account for the 1:1 stoichiometry between CaH2 and H2. This will give you the moles of CaH2 required, which you can then convert to grams.


What is the chemical reaction of Calcium hydride with water?

The chemical reaction of calcium hydride (CaH2) with water (H2O) results in the formation of calcium hydroxide (Ca(OH)2) and hydrogen gas (H2). The balanced chemical equation for this reaction is: CaH2 + 2H2O -> Ca(OH)2 + 2H2