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Since H2SO4 is a diprotic acid, it will require twice the amount of NaOH to neutralize it. Therefore, molarity of NaOH should also be 1 M.
1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, to neutralize 1 mole of H2SO4, 2 moles of NaOH are required.
To neutralize 1 mole of H2SO4 in 100 ml (0.1 L) of 1 M solution, you will need 0.1 moles of NaOH.
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How many NaOH required to neutralize complitly4.9 gms of H2SO4?
To neutralize sulfuric acid (H2SO4), which is a diprotic acid, you would need two moles of NaOH for every one mole of H2SO4. The molar mass of H2SO4 is 98.08 g/mol, so for 4.9 g of H2SO4, you would need (4.9 g / 98.08 g/mol) * 2 mol of NaOH for complete neutralization.
What is the number of moles of NaOH required to neutralize 1 mole of H2SO4?
2 moles of NaOH are required to neutralize 1 mole of H2SO4 because the reaction between NaOH and H2SO4 is 2:1 molar ratio.
What volume of 0.744 Molarity of NaOH is required to titrate 10.00ml of 0.526 M H2SO4?
The balanced chemical equation for the reaction between NaOH and H2SO4 is 2NaOH + H2SO4 ⟶ Na2SO4 + 2H2O. From the equation, it is a 1:1 ratio of NaOH to H2SO4. Therefore, to neutralize 10.00 ml of 0.526 M H2SO4, you will need the same amount of 0.526 M NaOH, which is 10.00 ml.
How many grams of sulfuric acid will neutralize 10.0 g of sodium hydroxide?
For every mole of sodium hydroxide, you need 1 mole of sulfuric acid for neutralization. The molar mass of sodium hydroxide (NaOH) is 40.0 g/mol and sulfuric acid (H2SO4) is 98.1 g/mol. So, to neutralize 40 g of NaOH (1 mole), you would need 98.1 g of H2SO4 (1 mole). Therefore, to neutralize 10.0 g of NaOH, you would need 24.53 g of H2SO4.
How many grams of sodium sulfate will be formed if you start with 12.5 grams of sodium hydroxide and you have an excess of sulfuric acid?
The balanced chemical equation for the reaction is 2NaOH + H2SO4 -> Na2SO4 + 2H2O. This shows that 2 moles of NaOH react with 1 mole of H2SO4 to form 1 mole of Na2SO4. Calculate the number of moles of NaOH (12.5g ÷ molar mass of NaOH) and then use the mole ratio from the balanced equation to find the moles of Na2SO4 formed. Finally, convert moles of Na2SO4 to grams using its molar mass.
How many NaOH required to neutralize complitly4.9 gms of H2SO4?
To neutralize sulfuric acid (H2SO4), which is a diprotic acid, you would need two moles of NaOH for every one mole of H2SO4. The molar mass of H2SO4 is 98.08 g/mol, so for 4.9 g of H2SO4, you would need (4.9 g / 98.08 g/mol) * 2 mol of NaOH for complete neutralization.
What is the number of moles of NaOH required to neutralize 1 mole of H2SO4?
2 moles of NaOH are required to neutralize 1 mole of H2SO4 because the reaction between NaOH and H2SO4 is 2:1 molar ratio.
What volume of 0.744 Molarity of NaOH is required to titrate 10.00ml of 0.526 M H2SO4?
The balanced chemical equation for the reaction between NaOH and H2SO4 is 2NaOH + H2SO4 ⟶ Na2SO4 + 2H2O. From the equation, it is a 1:1 ratio of NaOH to H2SO4. Therefore, to neutralize 10.00 ml of 0.526 M H2SO4, you will need the same amount of 0.526 M NaOH, which is 10.00 ml.
How many grams of sulfuric acid will neutralize 10.0 g of sodium hydroxide?
For every mole of sodium hydroxide, you need 1 mole of sulfuric acid for neutralization. The molar mass of sodium hydroxide (NaOH) is 40.0 g/mol and sulfuric acid (H2SO4) is 98.1 g/mol. So, to neutralize 40 g of NaOH (1 mole), you would need 98.1 g of H2SO4 (1 mole). Therefore, to neutralize 10.0 g of NaOH, you would need 24.53 g of H2SO4.
How many grams of sodium sulfate will be formed if you start with 12.5 grams of sodium hydroxide and you have an excess of sulfuric acid?
The balanced chemical equation for the reaction is 2NaOH + H2SO4 -> Na2SO4 + 2H2O. This shows that 2 moles of NaOH react with 1 mole of H2SO4 to form 1 mole of Na2SO4. Calculate the number of moles of NaOH (12.5g ÷ molar mass of NaOH) and then use the mole ratio from the balanced equation to find the moles of Na2SO4 formed. Finally, convert moles of Na2SO4 to grams using its molar mass.
How many grams of NaOH and H2SO4 are needed to produce 200 g Na2SO4?
To produce 200 g of Na2SO4, you would need 80 g of NaOH (sodium hydroxide) and 98 g of H2SO4 (sulfuric acid) based on their respective molar masses and stoichiometry in the balanced chemical equation for the reaction.
A 25.00ml sample of h2so4 requires 22.65 ml of the 0.550m naoh for its titration what was the concentration of sulfuric acid?
The balanced chemical equation for the reaction is H2SO4 + 2NaOH -> Na2SO4 + 2H2O. From the mole ratio, 1 mole of H2SO4 reacts with 2 moles of NaOH. Using the volume and concentration of NaOH, we can calculate the moles of NaOH used. Then, knowing the moles of NaOH used and the volume of H2SO4, we can find the concentration of sulfuric acid.
How many moles of NaOH react with 1 mole of H2SO4?
2 moles of NaOH will react with 1 mole of H2SO4 based on the balanced chemical equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
How many grams of NaOH would you need to make 4 litters of 8 M NaOH?
To calculate the grams of NaOH needed, use the formula: grams = molarity x volume x molar mass. First, convert the volume to liters (4 liters). Next, calculate the grams using 8 M as the molarity and the molar mass of NaOH. This will give you the amount of NaOH required to make 4 liters of 8 M NaOH solution.
How much 66 baume sulfuric acid is required to neutralize 350lbs of sodium hydroxide?
To neutralize sodium hydroxide with sulfuric acid, the molar ratio is 2:1 (2 moles of NaOH react with 1 mole of H2SO4). First, convert 350 lbs of NaOH to moles, then use the molar ratio to find the moles of H2SO4 needed. Finally, convert this to the required volume of 66 baume sulfuric acid.
Which salt is produced when H2SO4 reacts with NaOH?
When sulfuric acid (H2SO4) reacts with sodium hydroxide (NaOH), the salt produced is sodium sulfate (Na2SO4) along with water.
What mass of NaOH is required to make up 100 mL of a 0.5000 M solution?
Two parts.Molarity = moles of solute/Liters of solution ( 100 mL = 0.1 Liters )0.5000 M NaOH = X moles/0.1 L= 0.05 moles NaOH--------------------------------now,0.05 moles NaOH (39.998 grams/1 mole NaOH)= 1.99 grams NaOH required====================( could call it 2.00 grams )
