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The stomach is lined with a thick layer of mucus that helps protect its lining from the corrosive effects of hydrochloric acid (HCl). The mucus acts as a barrier, preventing the acid from damaging the stomach tissue. Additionally, the stomach has a rapid turnover of its lining cells, allowing damaged cells to be quickly replaced.
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How do you make 60 mL of a 0.1 M HCl solution from 6.0 M HCl?
To convert make a dillute solution from a concentrated one, take the amount of moles needed for the final solution as mL of concetrated solution, and dillute with water until the desired volume is reached.
How do you make 0.25N HCL from 1.00N HCL?
To make 0.25N HCl from 1.00N HCl, you would need to dilute the 1.00N HCl solution by adding three parts of water for every part of the original solution. For example, you can mix 1 mL of 1.00N HCl with 3 mL of water to obtain 0.25N HCl solution.
How do you make 25 ml of a 0.0010 M HCl starting with 0.010 M HCl?
To make 25 ml of 0.0010 M HCl from 0.010 M HCl: (0.010 M) x V1 = (0.0010 M) x 25 ml V1 = (0.0010 M * 25 ml) / 0.010 M V1 = 2.5 ml of the 0.010 M HCl solution should be diluted to 25 ml to get 0.0010 M HCl.
How many mL of HCL do you measure to prepare a liter of 0.5N HCL?
To prepare a liter of 0.5N HCl solution, you would measure 50 mL of concentrated hydrochloric acid (37% HCl by mass) and dilute it to 1 liter with distilled water.
How do you turn 1N of HCL into 0.001N of HCL?
You can dilute the 1N HCl solution by adding 999 parts of water to 1 part of the 1N HCl solution. For example, take 1 mL of 1N HCl and add it to 999 mL of water to create a 0.001N HCl solution.
How many ml of 0.43 m naoh will be needed to neutralize 10 ml of stomach acid if stomach acid is 0.1 m hcl?
Balanced equation first.NaOH + HCl -> NaCl + H2OAll one to one so a simple equality will do here.(X ml)(0.43 M NaOH) = (10 ml)(0.1 M HCl)0.43X = 1X = 2.3 milliliters NaOH needed--------------------------------------
How many ml of 6.00m hcl are needed to prepare 1000 ml of a 100m hcl?
100 M HCl don't exist.
How do you make 60 mL of a 0.1 M HCl solution from 6.0 M HCl?
To convert make a dillute solution from a concentrated one, take the amount of moles needed for the final solution as mL of concetrated solution, and dillute with water until the desired volume is reached.
How do you make 0.25N HCL from 1.00N HCL?
To make 0.25N HCl from 1.00N HCl, you would need to dilute the 1.00N HCl solution by adding three parts of water for every part of the original solution. For example, you can mix 1 mL of 1.00N HCl with 3 mL of water to obtain 0.25N HCl solution.
How many moles of HCl are in 3.36 mL of 22.22 M HCl and 81.5 mL of water?
0.0747mol/L of HCL 1.81mol/L of water
Ask us anythingprepare 250ml of 0.05N HCl from the 0.1N HCl .?
Mix 125 mL 0,1 N HCl with 125 mL water.
How do you make 25 ml of a 0.0010 M HCl starting with 0.010 M HCl?
To make 25 ml of 0.0010 M HCl from 0.010 M HCl: (0.010 M) x V1 = (0.0010 M) x 25 ml V1 = (0.0010 M * 25 ml) / 0.010 M V1 = 2.5 ml of the 0.010 M HCl solution should be diluted to 25 ml to get 0.0010 M HCl.
How many mL of HCL do you measure to prepare a liter of 0.5N HCL?
To prepare a liter of 0.5N HCl solution, you would measure 50 mL of concentrated hydrochloric acid (37% HCl by mass) and dilute it to 1 liter with distilled water.
How do you turn 1N of HCL into 0.001N of HCL?
You can dilute the 1N HCl solution by adding 999 parts of water to 1 part of the 1N HCl solution. For example, take 1 mL of 1N HCl and add it to 999 mL of water to create a 0.001N HCl solution.
How do you prepare 5N hcl solution?
520 ml of HCl in 480 ml of water=1000ml = 5 N
What volume of 3.0 M HCl sould be obtained to prepare 100 mL of 1.0 M HCL?
To prepare 100 mL of 1.0 M HCl from a 3.0 M stock solution, you can use the formula: (M_1V_1 = M_2V_2). Solving for V1: (3.0 M)(V1 mL) = (1.0 M)(100 mL), thus V1 = 33.3 mL. So, you would need to measure out 33.3 mL of the 3.0 M HCl solution and then dilute it to 100 mL to obtain 1.0 M HCl.
How do you prepare 500 ml 1N hcl from 10N HCl?
To prepare 500 ml of 1N HCl from 10N HCl, you need to dilute the 10N HCl with distilled water. Use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial concentration needed, C2 is the final concentration, and V2 is the final volume. In this case, the calculation would be 10 x V1 = 1 x 500. Solve for V1 to find the volume of 10N HCl needed, then add distilled water to make a total volume of 500 ml.
