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Na2O + H2O = 2NaOH
Sodium Oxide (Na2O) is a white crystalline solid.
Note the molar ratios are 1:1::2 or 1/2: 1/2 ::1
Hence
Its Mr is
2 x Na = 2 x 23 = 46
1 x O = 1 x 16 = 16
46 + 16 = 62
Using the equation
Moles = mass(g) / Mr
Then mass (g) = moles X
To prepare a 1 molar solution of sodium hydroxide (NaOH), you would dissolve 40 grams of NaOH pellets in enough water to make 1 liter of solution. This is because the molar mass of NaOH is approximately 40 g/mol. Be sure to wear appropriate safety gear and handle NaOH with care as it is a caustic substance.
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What is the molar mass of sodium and hydroxide?
The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of hydroxide (OH) is 17.01 g/mol. To find the molar mass of sodium hydroxide (NaOH), you can add the molar masses of sodium and hydroxide together, which equals 39.00 g/mol.
What is the density of 1 molar sodium hydroxide in grams per milliliter?
The density of a 1 M solution of sodium hydroxide is approximately 1.04 g/mL at room temperature.
What volume in mLs of 0.100 M sodium hydroxide solution must be added to 20.0 mL of 0.08 M sulfuric acid solution to reach the end point?
To neutralize the sulfuric acid completely, you need a 1:2 molar ratio of sodium hydroxide to sulfuric acid. Therefore, you would need to add twice the amount of sodium hydroxide compared to the amount of sulfuric acid, which is 40.0 mL of the sodium hydroxide solution.
How do you prepare 0.2M of anhydrous of sodium thiosulphate?
To prepare 0.2M solution of anhydrous sodium thiosulfate (Na2S2O3), you dissolve 24.6g of anhydrous Na2S2O3 in distilled water and dilute it to 1 liter. This is the molar mass method, where molar mass of Na2S2O3 is 158.10 g/mol.
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
First, calculate the number of moles of nitric acid present in 3.50 L of 0.700 M solution. Since nitric acid is a diprotic acid, the mole ratio with sodium hydroxide is 1:2. Then, use the mole ratio to determine the number of moles of sodium hydroxide needed to neutralize the nitric acid. Finally, convert the moles of sodium hydroxide to grams using its molar mass.
What is the density of 3 molar sodium hydroxide in grams per milliliter?
The density of a 3 molar solution of sodium hydroxide is approximately 1.11 grams per milliliter.
How do you prepare a 0.4 molar solution of sodium hydroxide from 96 percent sodium hydroxide pellets?
16.5g 97% pure NaOH pellets dissoved in 1 litre of distilled
What is the molar mass of sodium and hydroxide?
The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of hydroxide (OH) is 17.01 g/mol. To find the molar mass of sodium hydroxide (NaOH), you can add the molar masses of sodium and hydroxide together, which equals 39.00 g/mol.
What is the mass of sodium hudroxide needed to prepare 100 mL of a 0.10 M solution?
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To prepare a 0.10 M solution in 100 mL, you would need 1.0 g of NaOH. This can be calculated using the formula: mass (g) = molarity (M) x volume (L) x molar mass (g/mol).
What is the density of 1 molar sodium hydroxide in grams per milliliter?
The density of a 1 M solution of sodium hydroxide is approximately 1.04 g/mL at room temperature.
Given a 5 Molar sodium hydroxide Calculate how much 5 Molar base you need to make a 100 mL of a 1 M solution?
20 ml
What volume in mLs of 0.100 M sodium hydroxide solution must be added to 20.0 mL of 0.08 M sulfuric acid solution to reach the end point?
To neutralize the sulfuric acid completely, you need a 1:2 molar ratio of sodium hydroxide to sulfuric acid. Therefore, you would need to add twice the amount of sodium hydroxide compared to the amount of sulfuric acid, which is 40.0 mL of the sodium hydroxide solution.
What is the pH number of sodium hydroxide?
Sodium hydroxide does not have a pH number. The pH of a solution of sodium hydroxide depends entirely on the concentration of it in that solution. To learn how to determine the pH of a sodium hydroxide solution, see the Related Questions links.
How do you prepare 0.2M of anhydrous of sodium thiosulphate?
To prepare 0.2M solution of anhydrous sodium thiosulfate (Na2S2O3), you dissolve 24.6g of anhydrous Na2S2O3 in distilled water and dilute it to 1 liter. This is the molar mass method, where molar mass of Na2S2O3 is 158.10 g/mol.
How much water should be added to 98 mg of sodium azide to give a 1 molar solution?
To make a 1 molar solution of sodium azide, you would need to dissolve 65.01 g of sodium azide in water to make 1 liter of solution. Since you have 98 mg of sodium azide, you would need to add enough water to make a final volume of 1 liter to create the 1 molar solution.
How many grams of solid sodium hydroxide are required to prepare 400 milliliters of a 4 hundredth molar solution?
So you want 0.04M but you have 400ml, not a litre. 0.04/1000*400 is 0.016 moles wanted. 0.016*40 (molecular weight) is 0.64g
How many grams of sodium hydroxide are present in 675 mL of a 0.500M solution?
To calculate the grams of sodium hydroxide present in the solution, first calculate the number of moles using the formula: moles = Molarity (M) x Volume (L). Then, use the molar mass of sodium hydroxide (NaOH) to convert moles to grams. The molar mass of NaOH is 40 g/mol. Thus, in this case, you have 0.3375 moles of NaOH and if you convert this to grams, it would be 13.5 grams.
