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dilute 85ml of HCL to 1000ml This answer does not state which is the original concentration of the 85ml of HCL mentioned. The question should state what does the operator have initially (for example "I have HCl 87.5% (v/v; 7+1) solution and I want to get 1N solution of HCl, what should I do?"

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15y ago
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15y ago

37% HCl means 37 gms /100mL or 370 gms /litre.That means 370/36.5 M.Now to convert it to 0.1N HCl.

The normality and Molarity for HCl is same as HCl is a mono protonic acid.It means we have 370/36.5 N HCl.

Using N1V1 = N2V2;

Here N1 =370/36.5N, V1 = ? ( to be calculated);

N2 =0.1N , V2 = 1000 mL ( Assumed ) it can be any value you desire );

Or ( 370/36.5)N *V1 = 0.1N *1000

or V1 = 0.1N*1000/(370/36.5)N;

or V1 = 0.1*1000*36.5/370;

or V1 = 9.86 mL or 8.9mL;

So take 990.1 mL of water and mix 9.9 mL of acid in it to get 1000mL of 0.1N HCl.

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14y ago

Density of HCl: 1.48 g/ml

Molecular weight of HCl: 36.5g/mole

Concentration of HCl stock: 36%

Concentration of another HCl stock: 12N

Final volume: 1L

Let's assume that we're making a 1N HCl solution. Using the 36% concentration stock, we'll need to find out how many ml we would need. However, HCl is interesting because it has a higher density than water.

For a 1N solution (also known as 1M) however, you would need this amount of grams:

(1M HCl) x (36.5 g/ mole HCl) x (1L) = 36.5 grams.

Now we need the amount of ml from a 36% solution. This is different from having a known concentration like 10M, for example.

36% = 36 grams HCl / 100 grams of stock concentration solution

(36.5 grams HCl) x (100gram of stock solution/ 36 grams HCl) x (1 ml/ 1.48 grams) =

68.5ml

Dissolve 68.5ml of 36% solution into 931.5ml of ddH20.

If your stock concentration came in 12M, then using the following equation:

M = concentrations and V = volume.

M1V1 = M2V2

V1 = (M2V2 )/M1

Using the second equation,

V1 = volume of your stock concentration

M1 = concentration of your stock

V2 = volume of your final preparation

M2 = concentration of your final

V1 = (1 M x 1L )/(12M) = 0.083 L = 83ml

Dissolve 83 mL of 12M HCl into 917ml of ddH2O

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6mo ago

To prepare a 1N HCl solution, you would mix 36.46 grams of hydrochloric acid (HCl) in 1 liter of water. This is because 1N HCl solution means it contains 1 mole of HCl per liter of solution. Use proper safety precautions when handling concentrated acids.

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13y ago

Typically, to prepare 0.1 M HCL solution you will need to dilute it from the stock solution or concentrated HCL. I assume that you use concentrated HCL. Most concentrated HCL exist in 37.5%

As far as we know, 37.5% concetrated HCL is not a pure HCL. So, we need to do a bit of calculation to dilute it to the desired concentration. There are many ways of calculation but instead I will use the accurate calculation which is the Normality calculation for dilution.

The calculation method:

Grams of compound needed = (N desired)(equivalent mass)(volume in liters desired)

Volume of concentrated acid needed = (grams of acid needed)/(percent concentration x specific gravity)

Before we begin, you need to know what is Normality (N). Normality is used to measure the concentration of acid or base in the solution. Normality is similar to molarity as molarity measure the concentration of ions or compounds in a solution while normality represent the molar concentration of acid component or base component.

To know the normality, simply multiply the molarity with the number of hidrogen ions (H+) in the acid solution or hydroxide ions (OH-) in the base solution.

(*HCL only has 1 hidrogen ion)

Now to dilute 0.1 M HCL from 37.5% concentrated HCL solution, you need to find the normality first. Simply multiply 0.1 M with 1 will give you 0.1 N.

The equivalent mass is the molar mass divided by by the number of hydrogen ions.

Molar mass for HCL is 36.4611 g/mol. Since HCL only has one hydrogen ion, the equivalent mass will be 36.4611. The volume will be in 1 litre. HCL specific gravity is 1.189.

Insert the details in the formula,

Grams of compound needed = (0.1 N)(36.4611)(1 Litre) = 3.6461

Volume of concentrated acid needed = (3.6461)/(0.375 x 1.189) = 8.1774 ml

So, 8.1774 ml of 37.5% concentrated HCL is needed to prepare 0.1 M HCL.

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16y ago

To prepare 1N HCl take 8.33 ml of 12N HCl and make up to 100 ml

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16y ago

add 8.28ml of 37% HCL in 100 ml distilled water to prepare 1N HCL solution!

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15y ago

if you want to 250ml 1M of hydrochloric acid ,you need to add 21ml 12M(37-38%)hydrochloric acid to 229ml water

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14y ago

1M=36.5g in 1000ml water,3M=109.5g in 1000ml=10.95g in100ml

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15y ago

Use C1V1 = C2V2

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Q: How do you prepare a 1N HCl solution?
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How do you prepare 1N hcl to 6N hcl?

To prepare 6N HCl from 1N HCl, you can dilute the 1N HCl by adding 6 times the volume of water to the 1N HCl solution. For example, mix 1 volume of 1N HCl with 6 volumes of water to get a final concentration of 6N HCl. Make sure to add acid to water slowly with stirring to avoid splashes and heat generation.


How do you turn 1N of HCL into 0.001N of HCL?

You can dilute the 1N HCl solution by adding 999 parts of water to 1 part of the 1N HCl solution. For example, take 1 mL of 1N HCl and add it to 999 mL of water to create a 0.001N HCl solution.


How do you standardization 1N hcl?

To standardize 1N HCl (hydrochloric acid), you would typically use a primary standard base, such as sodium hydroxide (NaOH), of known concentration to titrate the HCl solution. By carefully titrating the HCl with the NaOH, you can determine the exact concentration of the HCl solution. This information can then be used to adjust the concentration of the HCl solution as needed to make it accurately 1N.


How 1m hcl is equal to 1n hcl?

1M HCl means there is 1 mole of HCl in 1 liter of solution. To convert to 1N HCl, you need to consider the equivalent weight of HCl, which is its molecular weight as it is a monoprotic acid. So, in this case, 1M HCl is equivalent to 1N HCl.


Calculaton of 1N HCl preparation?

To prepare 1N HCl solution, you would need to dissolve 36.46 grams of concentrated hydrochloric acid (HCl) in enough water to make 1 liter of solution. This concentration corresponds to a normality of 1N for HCl. It is important to handle concentrated acid with care and dilute it slowly by adding it to the water while stirring.

Related questions

How do you prepare 1N hcl to 6N hcl?

To prepare 6N HCl from 1N HCl, you can dilute the 1N HCl by adding 6 times the volume of water to the 1N HCl solution. For example, mix 1 volume of 1N HCl with 6 volumes of water to get a final concentration of 6N HCl. Make sure to add acid to water slowly with stirring to avoid splashes and heat generation.


How do you turn 1N of HCL into 0.001N of HCL?

You can dilute the 1N HCl solution by adding 999 parts of water to 1 part of the 1N HCl solution. For example, take 1 mL of 1N HCl and add it to 999 mL of water to create a 0.001N HCl solution.


How do you standardization 1N hcl?

To standardize 1N HCl (hydrochloric acid), you would typically use a primary standard base, such as sodium hydroxide (NaOH), of known concentration to titrate the HCl solution. By carefully titrating the HCl with the NaOH, you can determine the exact concentration of the HCl solution. This information can then be used to adjust the concentration of the HCl solution as needed to make it accurately 1N.


How 1m hcl is equal to 1n hcl?

1M HCl means there is 1 mole of HCl in 1 liter of solution. To convert to 1N HCl, you need to consider the equivalent weight of HCl, which is its molecular weight as it is a monoprotic acid. So, in this case, 1M HCl is equivalent to 1N HCl.


Calculaton of 1N HCl preparation?

To prepare 1N HCl solution, you would need to dissolve 36.46 grams of concentrated hydrochloric acid (HCl) in enough water to make 1 liter of solution. This concentration corresponds to a normality of 1N for HCl. It is important to handle concentrated acid with care and dilute it slowly by adding it to the water while stirring.


How do you make 1N HCL from 1N HCL?

Take specific volume of 3N solution and increase the volume three times by adding distilled water.


How do you prepare 100ml of 1N hcl?

To prepare 100 ml of 1N HCl, you would need to dilute 8.4 ml of concentrated hydrochloric acid (37% w/w) with distilled water to a total volume of 100 ml.


How do you prepare 0.02 M of HCl?

To prepare a 0.02 M solution of HCl, you would need to dilute concentrated HCl solution with a calculated amount of water. For example, to prepare 1 liter of 0.02 M HCl solution, you would mix 4.2 ml of concentrated HCl (12 M) with 995.8 ml of water. Always add acid to water slowly and with stirring to avoid splattering.


How to prepare 1N HCl solution?

To prepare a 1N (normal) HCl solution, you need to dilute concentrated hydrochloric acid (37%) by adding the appropriate amount of water to reach a final volume. For example, to prepare 1L of 1N HCl, you would mix approximately 83.3mL of concentrated HCl with distilled water to make a total volume of 1L. Make sure to add acid to water slowly with stirring due to the exothermic nature of the reaction.


How do you prepare 1N Hcl solution Dont tell in gL how much ml is required?

To prepare 1N HCl solution, you need to dilute concentrated HCl (usually 37% w/w) with water to get the desired concentration. For a 1N HCl solution, you would mix 1 part of concentrated HCl with 9 parts of water (ratio of 1:9). The volume needed would depend on the final volume required and the concentration of the concentrated HCl you start with.


How to calculate pH of 1N HCl solution?

The pH of a 1N HCl solution can be calculated using the formula pH = -log[H+], where [H+] is the concentration of H+ ions in the solution. For a 1N solution of HCl, the concentration of H+ ions will be 1M, so the pH will be -log(1) = 0.


How do you prepare the 10N HCl solution?

To prepare a 10N (10 normal) HCl solution, you would need to dilute concentrated hydrochloric acid (usually around 37% w/w) with water to achieve a final concentration where 1 L of solution contains 10 moles of HCl. It is important to follow safety precautions when handling concentrated acid, such as wearing appropriate protective gear and adding acid to water slowly to avoid splashing.