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Since HCl is a monoprotic acid, its normality is the same as its molarity. A 4 N solution of HCl is a 4 M solution of HCl as well. If you want to make a liter of a 4 N solution of HCl, you need to dilute a certain volume of a standard solution you already have to one liter (1,000 mL) of the 4 M solution. You could use a standard concentrated solution of HCl that is usually 12 M using the following equation:

(V1)(M1) = (V2)(M2)

V1 = ?

M1 = 12 M

V2 = 1,000 mL

M2 = 4 M

V1 = [(V2)(M2)] / ((M1)

V1 = [(1,000 mL)(4 M)] / (12 M)

V1 = 83 mL

According to the above calculations, to make 1,000 mL (1 L) of a 4 M solution of HCl, you would need to dilute with water 83 mL of 12 M solution of HCl to 1,000 mL (1 L) volume. As stated before, a 4 M solution is also a 4 N solution of HCl.

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12y ago
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6mo ago

To make 500mL of 3N NaOH solution, you need to dissolve 15g of NaOH pellets in enough water to make 500mL of solution. Calculate the amount of NaOH needed by using the formula: (g = (N \times M \times V) / 1000), where (N = normality (3N)), (M = molar mass of NaOH (40 g/mol)), and (V = volume in liters (0.5 L)).

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12y ago

1N = 40.0g in 1000mL (1M or 1mol/L)

3N = 120.0g in 1000mL (3M or 3mol/L).

Therefore 3N (3M) in 500mL = 60g NaOH.

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13y ago

Take 28.21 ml Hcl make up to 1000 ml Dis.Water its 3N HCl

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12y ago

25.5ml hcl in 100ml of water

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Q: How do you make 500ml of 3N NaOH?
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What is 3N NaOH?

3N NaOH refers to a solution of sodium hydroxide (NaOH) that has a concentration of 3 normal (N), meaning it contains 3 moles of NaOH per liter of solution. This concentration is commonly used in laboratory settings for various chemical reactions and titrations.


How many grams of solid NaOH are needed to prepare 500mL NaOH solution with a concentration of 0.4M?

To prepare a 0.4M NaOH solution in 500mL, you would need 20g of solid NaOH. This is calculated by multiplying the molarity by the volume in L and the molar mass of NaOH. (0.4 mol/L) * (0.5 L) * (40 g/mol) = 20g.


How many grams of NaOH are contained in 500mL of 0.5M NaOH?

To calculate the grams of NaOH in 500mL of 0.5M NaOH, you first need to find the moles of NaOH present in 500mL, which is 0.25 moles. Then, use the molar mass of NaOH (40g/mol) to convert moles to grams. So, in 500mL of 0.5M NaOH, there are 10 grams of NaOH.


How many grams of naoh are needed to prepare 500ml of 125M naoh?

To calculate the grams needed, first find the molarity of the solution, which is 125 moles/liter. Then convert the volume to liters (500ml = 0.5 liters) and multiply the molarity by the volume in liters to find the number of moles needed. Finally, multiply the moles by the molar mass of NaOH (40 g/mol) to find the grams needed. In this case, it would be 31.25 grams of NaOH.


How is a solution of NaOH prepared dissolving 20g of NaOH in 500ml of distiled water solved?

To prepare a 20 g/500 mL solution of NaOH, you would gradually add 20 g of NaOH to 500 mL of distilled water while stirring until fully dissolved. It is important to add the solid to the liquid to prevent splattering. Remember to always use caution and appropriate personal protective equipment when handling NaOH due to its caustic nature.

Related questions

What is 3N NaOH?

3N NaOH refers to a solution of sodium hydroxide (NaOH) that has a concentration of 3 normal (N), meaning it contains 3 moles of NaOH per liter of solution. This concentration is commonly used in laboratory settings for various chemical reactions and titrations.


What is the resulting molarity when 100.00mL of a 0.125 M NaOH solutions is diluted to 500mL?

The moles of NaOH in the original solution is 0.125 M x 0.100 L = 0.0125 moles. When diluted to 500 mL, the new molarity will be 0.0125 moles / 0.500 L = 0.025 M.


How many grams of solid NaOH are needed to prepare 500mL NaOH solution with a concentration of 0.4M?

To prepare a 0.4M NaOH solution in 500mL, you would need 20g of solid NaOH. This is calculated by multiplying the molarity by the volume in L and the molar mass of NaOH. (0.4 mol/L) * (0.5 L) * (40 g/mol) = 20g.


How many grams of NaOH are contained in 500mL of 0.5M NaOH?

To calculate the grams of NaOH in 500mL of 0.5M NaOH, you first need to find the moles of NaOH present in 500mL, which is 0.25 moles. Then, use the molar mass of NaOH (40g/mol) to convert moles to grams. So, in 500mL of 0.5M NaOH, there are 10 grams of NaOH.


How many grams of naoh are needed to prepare 500ml of 125M naoh?

To calculate the grams needed, first find the molarity of the solution, which is 125 moles/liter. Then convert the volume to liters (500ml = 0.5 liters) and multiply the molarity by the volume in liters to find the number of moles needed. Finally, multiply the moles by the molar mass of NaOH (40 g/mol) to find the grams needed. In this case, it would be 31.25 grams of NaOH.


what is (3n)(3n-1)?

(3n)(3n-1) = 3n * 3n - 3n * 1 Now, perform the multiplication: (3n * 3n) = 9n^2 (3n * 1) = 3n So, (3n)(3n-1) simplifies to: 9n^2 - 3n


How do you get this 3n plus 2 plus (3n plus 3 - 3n plus 1)?

3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6


How is a solution of NaOH prepared dissolving 20g of NaOH in 500ml of distiled water solved?

To prepare a 20 g/500 mL solution of NaOH, you would gradually add 20 g of NaOH to 500 mL of distilled water while stirring until fully dissolved. It is important to add the solid to the liquid to prevent splattering. Remember to always use caution and appropriate personal protective equipment when handling NaOH due to its caustic nature.


What is the Greatest Common Factor of 3n2 and 3n?

Is it a. 3n square and 3n ans. 3n b. 3n *2 and 3n ans.3n ans. 3n for both!!


How do you prepare 0.6 N NaOH solution?

for NaOH normality = molarity ; hence for 1M(1N) solution you have to dissolve 40 g NaOH in 1L water ...... therfore for 0.1 N soln you have to dissolve 4 g in 1 L water and then standerized it with acid which has known normality


What is 3n times 3n?

The expression 3n times 3n can be simplified by multiplying the coefficients (3 * 3) and adding the exponents (n + n). This results in 9n^2, where n is raised to the power of 2. This simplification follows the rules of exponentiation, specifically the rule that states when multiplying two terms with the same base, you add the exponents.


Can we make 1N NaOH solution from 0.1N NaOH solution?

Yes, you can make a 1N NaOH solution from a 0.1N NaOH solution by diluting it 10 times. For example, to make 1 liter of 1N NaOH solution, you would mix 100 ml of the 0.1N NaOH solution with 900 ml of water.