To make a 1 molar solution of sodium (Na), you would dissolve 23 grams of sodium metal into enough water to make 1 liter of solution. This would provide you with a solution where the concentration of Na ions is 1 mole per liter. Note that sodium is highly reactive with water, so the process should be done with caution.
To make 10 gallons of a 50% sodium hydroxide solution, you would need 10 pounds of sodium hydroxide. This is because the percentage indicates the weight of sodium hydroxide in the solution. Hence, in a 50% solution, half of the weight of the solution is sodium hydroxide.
To prepare a 0.01N solution of sodium metabisulfite, you would need 2.31 grams of sodium metabisulfite per liter of solution.
To make a 0.25 mol solution of sodium nitrite, measure out 8.25 grams of sodium nitrite (NaNO2) (sodium nitrite has a molar mass of 69.01 g/mol) and dissolve it in enough water to make a total volume of 1 liter. This will give you a 0.25 mol/L solution of sodium nitrite.
Yes, you can make sodium acetate from baking soda. First, create a solution of baking soda and vinegar. Then heat the solution to drive off carbon dioxide and leave behind sodium acetate. Allow the solution to cool and crystallize to obtain solid sodium acetate.
To make a 2% sodium hypochlorite solution from a 12% solution, you can set up the equation: 12% solution * x litres = 2% solution * 100 litres Solving for x, you get: x = (2% solution * 100 litres) / 12% = 16.67 litres Therefore, you would need 16.67 litres of the 12% sodium hypochlorite solution to make 100 litres of a 2% solution.
To make 10 gallons of a 50% sodium hydroxide solution, you would need 10 pounds of sodium hydroxide. This is because the percentage indicates the weight of sodium hydroxide in the solution. Hence, in a 50% solution, half of the weight of the solution is sodium hydroxide.
To prepare a 0.01N solution of sodium metabisulfite, you would need 2.31 grams of sodium metabisulfite per liter of solution.
To make a 0.25 mol solution of sodium nitrite, measure out 8.25 grams of sodium nitrite (NaNO2) (sodium nitrite has a molar mass of 69.01 g/mol) and dissolve it in enough water to make a total volume of 1 liter. This will give you a 0.25 mol/L solution of sodium nitrite.
To make a 7.5% solution of sodium carbonate in water, add 7.5 grams of sodium carbonate to 100 mL of water and stir until the sodium carbonate is completely dissolved. This will give you a 7.5% (w/v) solution of sodium carbonate.
To make a 1.0 M solution of sodium cation using sodium chloride, you need to consider the molar mass of sodium chloride (58.44 g/mol). Since 1 mole of sodium chloride provides 1 mole of sodium cation, you would need 58.44 g of sodium chloride to make a 1.0 M solution in 100 ml.
Yes, you can make sodium acetate from baking soda. First, create a solution of baking soda and vinegar. Then heat the solution to drive off carbon dioxide and leave behind sodium acetate. Allow the solution to cool and crystallize to obtain solid sodium acetate.
1molar=58.44gmol as given so,58.44-1000ml ? -200ml ans=58.44.200 ---- 1000 =
Just a solution of sodium hydroxide in water.
To make a 2% sodium hypochlorite solution from a 12% solution, you can set up the equation: 12% solution * x litres = 2% solution * 100 litres Solving for x, you get: x = (2% solution * 100 litres) / 12% = 16.67 litres Therefore, you would need 16.67 litres of the 12% sodium hypochlorite solution to make 100 litres of a 2% solution.
To make a 1M solution of sodium chloride in 1 liter of water, you would need 58.44 grams of sodium chloride. This is based on the molecular weight of sodium chloride, which is 58.44 g/mol.
2.5 g of Nacl is to be dissolve in 100ml of water gives 10ppm of Na solution.
To make a 10% solution of sodium metabisulfite, you would need 10 grams of sodium metabisulfite per 100 ml of solution. If you want to make a larger volume, you would adjust the amount of sodium metabisulfite accordingly.