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I believe S has an expanded octet and forms 6 bonds to the O atoms (2 are double and two are single).

When you draw this out you have two of the Oxygen atoms with only 7 electrons in their outer shells. At this point add an electron into each outer-shell to make it up to 8. These two extra electrons give the ion its overall charge of 2-.

You must put square-brackets around the whole diagram and show the charge in the top-right corner.

My tip is to use dots for the O electrons and add "filled-in" dots to show they came from elsewhere.

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βˆ™ 14y ago
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βˆ™ 7mo ago

In the dot and cross diagram of the sulfate ion (SO4^2-), sulfur is the central atom bonded to four oxygen atoms. Sulfur forms double bonds with two oxygen atoms and single bonds with the other two oxygen atoms. The formal charges on the oxygen atoms are 0, while the formal charge on the sulfur atom is -2.

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Q: How do you draw the Dot and Cross diagram of the Sulphate Ion?
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