First O has an oxidation number of -2; K will an oxidation number of +1 as it is an alkali metal. Therfore the Mn is +6. note that while the manganate ion exists, the question may relate to the permanganate ion MnO4-, so KMnO4, where Mn has oxidation number of +7
Chat with our AI personalities
To calculate the oxidation number of Mn in KMnO4, set up an equation using the known oxidation numbers of potassium (+1) and oxygen (-2). Since KMnO4 is a neutral compound, the sum of the oxidation numbers must equal zero. Thus, the oxidation number of Mn can be calculated by solving the equation: 2(+1) + x + 4(-2) = 0, where x represents the oxidation number of Mn. Solving for x gives Mn a +7 oxidation number.
The oxidation number of Mn in KMnO4 is +7. This can be determined by assigning the known oxidation numbers of potassium (+1) and oxygen (-2) and solving for the unknown oxidation number of manganese.
In K2MnO4, the oxidation state of oxygen is -2, and the overall charge of the compound is -1. Given that potassium has a +1 oxidation state, the oxidation state of manganese (Mn) in this compound is +7.
The oxidation number of manganese (Mn) can vary depending on the compound it is in. In MnO2, the oxidation number of Mn is +4, while in KMnO4, the oxidation number of Mn is +7.
In MnO2, the oxidation number of oxygen is typically -2. Since there are two oxygen atoms in MnO2, the total oxidation number contributed by oxygen is -4. The overall charge of the compound is neutral, so the oxidation number of manganese (Mn) can be calculated by setting the total oxidation number equal to zero. Therefore, the oxidation number of Mn in 2MnO2 is +4.
I assume you mean the oxidation number of Mn in the permanganate ion , MnO4- The sum of the oxidation numbers is the charge on a polyatomic ion so Mn has an oxidation number of +7 as each O is assigned -2.