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First O has an oxidation number of -2; K will an oxidation number of +1 as it is an alkali metal. Therfore the Mn is +6. note that while the manganate ion exists, the question may relate to the permanganate ion MnO4-, so KMnO4, where Mn has oxidation number of +7

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To calculate the oxidation number of Mn in KMnO4, set up an equation using the known oxidation numbers of potassium (+1) and oxygen (-2). Since KMnO4 is a neutral compound, the sum of the oxidation numbers must equal zero. Thus, the oxidation number of Mn can be calculated by solving the equation: 2(+1) + x + 4(-2) = 0, where x represents the oxidation number of Mn. Solving for x gives Mn a +7 oxidation number.

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Q: How do you calculate the the oxidation number of mn in k2mno4?
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