To calculate the excess moles of acid in a titration, subtract the moles of base used from the initial moles of acid. This will give you the amount of acid that was not neutralized by the base and therefore the excess moles of acid present in the solution.
To determine the concentration of the base (LiOH) in a titration, you would need information such as the volume of the base used and the volume of the acid titrated. By using the balanced chemical equation and stoichiometry, you can calculate the concentration of the base.
Using the mass of the base and volume of the acid, you can calculate the molarity of the base. Then, using the volume of acid required to reach the endpoint, you can calculate the molarity of the acid. Finally, use the stoichiometry between the base and acid to determine the molar mass of the unknown base.
To calculate the concentrations of the acid and base in a buffer solution from its pH, you need to know the pKa of the acid in the buffer. From the given pH, you can calculate the ratio of [A-]/[HA] using the Henderson-Hasselbalch equation. Once you have this ratio, you can determine the concentrations of both the acid and base in the buffer solution.
To determine the concentration of the base (NaOH) in a titration, you would use the volume of the base added and the volume and concentration of the acid (typically HCl). By using the balanced chemical equation and the volume and concentration of the acid, you can calculate the concentration of the base.
You can find the diameter of a cylinder by using the formula for pressure at the base of a cylinder (P = F/A) and the formula for the area of a circle (A = πr^2) where r is the radius of the base. Once you calculate the force acting on the base of the cylinder, you can find the diameter using the formula D = 2r, where D is the diameter.
The Pressure is .434 times the height The FORCE takes a lot more calculations as the height and the weight of the water has to be calculated in plus the hydra-static pressure
Assumptions:Density of water = 1000 kgm-3.Gravitational acceleration = 9.81 ms-2To calculate the pressure head of a 1 m depth of water, it is necessary to find the unit weight:Unit Weight = Density x gravityUnit Weight = 9810 Nm-3To calculate the pressure head at the base of the column of water:Pressure = Unit Weight x DepthPressure = 9810 x 1Pressure = 9810 PaThe resulting pressure is 9.81 kPa.
what the base word for calculator
It is the Latin base word.
what is the atmospheric pressure base in Pennsylvania
base of a mountain
The same as you would calculate any other area. For example, if the base happens to be rectangular, you multiply length x width.
bigger base + smaller base x height/2
On base percentage plus slugging percentage
You usually calculate it with a pH stick. Good question!!.
Every 2.3077 feet of water in a column increases the water pressure at the bottom of the column by 1 pound per square inch.A 39 foot column of water with a pressure of 120 psi at the base will have a pressure exerted on its top surface of 103.1 psi.39 ft/ 2.3077 ft/1 psi = 16.9 psi ; 120 psi -16.9 psi = 103.1 psievery meter of water in a column increases the pressure at the base of the column by 0.1 kg./ sq. cm (or 1 kilopascal)A 12 meter column of water exerts a pressure at its base of 12 kPa. (or 1.2 kg/sq. cm)