Because C and Fe appear in uncombined, atomic form in this equation we can ignore them initially and just look at the Fe2O3 and CO2. There are an odd number of atoms of O in the Fe2O3 and a odd number in the CO2. If I just double the number of molecules of Fe2O3 going into the reaction then this will also double the number of atoms of oxygen, thereby making the number even(which is what I want, eh). Here's what I have so far:
2 Fe2O3 + C -> Fe + CO2
Because there are six oxygen atoms on the left there must be six on the right. Therefore there are three CO2 molecules:
2 Fe2O3 + C -> Fe + 3 CO2
Finally:
2 Fe2O3 + 3 C -> 4 Fe + 3 CO2
This equation is not balanced as given. To balance it, you need to change the coefficients of the reactants and products. The balanced equation is 4Al + 3O2 -> 2Al2O3.
The equation FeSO4 = Fe2O3 + SO2 + SO3 is not balanced. To balance it, one possible balanced equation could be: 2FeSO4 = Fe2O3 + 2SO2 + 2SO3.
The balance equation would be 4Fe + 3O2 ==> 2Fe2O3, so the coefficients are 4, 3, 2.
The balanced equation for FeS2 + H2O + O2 -> Fe2O3 + H2SO4 is: 4FeS2 + 14H2O + 17O2 -> 8Fe2O3 + 8H2SO4. This balanced equation ensures that the number of each type of atom is the same on both sides of the equation.
The balanced equation for the reaction is: 3Fe2O3 + 3CO β 2Fe + 3CO2. This equation ensures that the number of atoms for each element is the same on both sides of the equation.
This equation is not balanced as given. To balance it, you need to change the coefficients of the reactants and products. The balanced equation is 4Al + 3O2 -> 2Al2O3.
To balance the chemical equation for the reaction of Al and Fe2O3 to produce Al2O3 and Fe, you need to ensure that the number of atoms for each element is the same on both sides of the equation. First, write the unbalanced equation: Al + Fe2O3 -> Al2O3 + Fe. Then, adjust the coefficients of each compound until the number of atoms of each element balances out. Solution: 2Al + Fe2O3 -> Al2O3 + 2Fe.
The equation FeSO4 = Fe2O3 + SO2 + SO3 is not balanced. To balance it, one possible balanced equation could be: 2FeSO4 = Fe2O3 + 2SO2 + 2SO3.
The balance equation would be 4Fe + 3O2 ==> 2Fe2O3, so the coefficients are 4, 3, 2.
The balanced equation for FeS2 + H2O + O2 -> Fe2O3 + H2SO4 is: 4FeS2 + 14H2O + 17O2 -> 8Fe2O3 + 8H2SO4. This balanced equation ensures that the number of each type of atom is the same on both sides of the equation.
The balanced equation for the reaction is: 3Fe2O3 + 3CO β 2Fe + 3CO2. This equation ensures that the number of atoms for each element is the same on both sides of the equation.
3Fe + 4(H2O) ---> Fe3O4 + 4(H2) You really should learn this, its not that hard =D
The balanced equation for the extraction of iron from its ore involves the reaction of iron oxide (Fe2O3) with carbon monoxide (CO) to produce iron (Fe) and carbon dioxide (CO2). The balanced chemical equation is: Fe2O3(s) + 3CO(g) β 2Fe(l) + 3CO2(g).
The balanced chemical equation is: 4FeS2 + 11O2 β 2Fe2O3 + 8SO2 The reaction is a combination of iron pyrite (FeS2) and oxygen (O2) to form iron(III) oxide (Fe2O3) and sulfur dioxide (SO2).
The balanced chemical equation for this reaction is: 2 Fe2O3 + 6 HNO3 β 2 Fe(NO3)3 + 3 H2O
To determine the grams of carbon needed to react with 2.50 moles of Fe2O3, you first need to balance the equation for the reaction between C and Fe2O3. Then, calculate the molar ratio between C and Fe2O3 from the balanced equation. Finally, use the molar mass of carbon to convert the moles of carbon to grams.
The balanced chemical equation for the formation of Fe2O3 from Fe and O is: 4Fe + 3O2 -> 2Fe2O3