0
To balance the equation K2Cr2O7 + H2SO4 + C3H8O3, start by balancing the elements that appear in only one reactant and one product. Then balance the oxygen atoms by adding water molecules. Finally, balance the hydrogen atoms by adding H+ ions. Adjust the coefficients as needed to ensure the equation is balanced.
3 C3H8O3 + 7 K2Cr2O7 + 28 H2SO4 = 7 K2SO4 + 7 Cr2(SO4)3 + 9 CO2 + 40 H2O
This question seems Impossible to answer. Because, Not enough information is given. What isC3H8O3. Maybe glycerol I think.
2KNO3 + H2CO3 ==> K2CO3 + 2HNO3 would be the balanced equation but since all of the species are ionizable and soluble, this reaction won't actually take place.
Add your answer:
Earn +20 pts
How do you balance k2cr2o7 h2so4 c2h5oh -- cr2so43 k2so4 ch3cooh h2o?
To balance this chemical equation, first balance the chromium atoms by adding a coefficient of 3 in front of Cr2(SO4)3. Next, balance the hydrogen atoms with a coefficient of 8 in front of H2O. Then, balance the oxygen atoms by adding a coefficient of 7 in front of H2SO4. Finally, balance the potassium atoms by adding a coefficient of 4 in front of K2SO4. The balanced equation is: K2Cr2O7 + 4H2SO4 + 3C2H5OH → Cr2(SO4)3 + K2SO4 + 3CH3COOH + 11H2O
Why H2SO4 is added in K2Cr2O7 during oxidation of alcohol?
H2SO4 is added in the oxidation of alcohols with K2Cr2O7 as a catalyst to provide acidic conditions, which facilitate the oxidation reaction. The sulfuric acid protonates the alcohol to form an oxonium ion, which is more easily oxidized by the chromate ion in K2Cr2O7. This helps to increase the efficiency and speed of the oxidation process.
What are the coefficients in K2Cr2O7 H2SO4 C2H5OH --- Cr2SO43 K2SO4 CH3COOH H2O?
The coefficients for the given chemical reaction are: K2Cr2O7: 1 H2SO4: 8 C2H5OH: 3 Cr2(SO4)3: 3 K2SO4: 3 CH3COOH: 3 H2O: 7
How prepare 0.1 n k2cr2o7?
To prepare a 0.1 N solution of K2Cr2O7 (potassium dichromate), you would need to dissolve 4.903 grams of K2Cr2O7 in enough water to make 1 liter of solution. Weigh out the exact amount of K2Cr2O7 using a balance, then dissolve it in water and make up the volume to 1 liter. This will give you a 0.1 N solution of K2Cr2O7.
What is the oxidation equation of the reaction of propanal with potassium dichromate?
The oxidation of propanal (CH3CH2CHO) by potassium dichromate (K2Cr2O7) in acidic conditions produces propanoic acid (CH3CH2COOH). The oxidation equation is: CH3CH2CHO + K2Cr2O7 + H2SO4 → CH3CH2COOH + Cr2(SO4)3 + K2SO4 + H2O.
How do you balance k2cr2o7 h2so4 c2h5oh -- cr2so43 k2so4 ch3cooh h2o?
To balance this chemical equation, first balance the chromium atoms by adding a coefficient of 3 in front of Cr2(SO4)3. Next, balance the hydrogen atoms with a coefficient of 8 in front of H2O. Then, balance the oxygen atoms by adding a coefficient of 7 in front of H2SO4. Finally, balance the potassium atoms by adding a coefficient of 4 in front of K2SO4. The balanced equation is: K2Cr2O7 + 4H2SO4 + 3C2H5OH → Cr2(SO4)3 + K2SO4 + 3CH3COOH + 11H2O
Why H2SO4 is added in K2Cr2O7 during oxidation of alcohol?
H2SO4 is added in the oxidation of alcohols with K2Cr2O7 as a catalyst to provide acidic conditions, which facilitate the oxidation reaction. The sulfuric acid protonates the alcohol to form an oxonium ion, which is more easily oxidized by the chromate ion in K2Cr2O7. This helps to increase the efficiency and speed of the oxidation process.
What is the formula for patassium dichromate?
The chemical formula for potassium dichromate is K2Cr2O7.
In the complete combustion of C3H8O3 how many moles of carbon dioxide are produced when 23.0g of C3H8O3 burns?
To calculate the moles of CO2 produced during the combustion of C3H8O3, you need to first balance the chemical equation. The balanced equation is C3H8O3 + 4.5O2 -> 3CO2 + 4H2O. Next, calculate the number of moles of C3H8O3 by dividing the given mass by its molar mass (92g/mol). Then, use the stoichiometry of the balanced equation to determine the moles of CO2 produced (3 moles of CO2 for every 1 mole of C3H8O3 burned).
What are the coefficients in K2Cr2O7 H2SO4 C2H5OH --- Cr2SO43 K2SO4 CH3COOH H2O?
The coefficients for the given chemical reaction are: K2Cr2O7: 1 H2SO4: 8 C2H5OH: 3 Cr2(SO4)3: 3 K2SO4: 3 CH3COOH: 3 H2O: 7
How prepare 0.1 n k2cr2o7?
To prepare a 0.1 N solution of K2Cr2O7 (potassium dichromate), you would need to dissolve 4.903 grams of K2Cr2O7 in enough water to make 1 liter of solution. Weigh out the exact amount of K2Cr2O7 using a balance, then dissolve it in water and make up the volume to 1 liter. This will give you a 0.1 N solution of K2Cr2O7.
What is the oxidation equation of the reaction of propanal with potassium dichromate?
The oxidation of propanal (CH3CH2CHO) by potassium dichromate (K2Cr2O7) in acidic conditions produces propanoic acid (CH3CH2COOH). The oxidation equation is: CH3CH2CHO + K2Cr2O7 + H2SO4 → CH3CH2COOH + Cr2(SO4)3 + K2SO4 + H2O.
How do you balance FeO H2SO4?
To balance the chemical equation FeO + H2SO4 → Fe2(SO4)3 + H2O, you would need to adjust the coefficients of the compounds. One balanced equation would be 3FeO + H2SO4 → Fe2(SO4)3 + H2O.
Product of potassium dicromate reacting with sulfur dioxide?
K2Cr2O7(aq) + 3SO2(g) + H2SO4(aq) Cr2(SO4)3(aq) + K2SO4(aq) + H2O(l)
Balance an equation by oxidation method?
To balance an equation using the oxidation method, identify the atoms undergoing oxidation and reduction. Add the necessary coefficients for each species to balance the change in oxidation states. Ensure mass balance by adjusting coefficients for other elements if needed. Finally, verify that the charges are balanced on both sides of the equation.
Why do you use 0.005M h2so4 solution for preparation of k2cr2o7 solution for UV calibration?
A 0.005M H2SO4 solution is used to prepare a K2Cr2O7 solution for UV calibration because it provides an acidic medium, which helps stabilize the dichromate Cr(VI) ions in the K2Cr2O7 solution. This stability ensures consistent and accurate UV calibration readings. Additionally, the specific concentration of H2SO4 is chosen to maintain a controlled environment for the reaction and analysis process.
How do you balance NaOH plus H2SO4?
To balance the reaction between NaOH and H2SO4, you first write out the unbalanced equation: NaOH + H2SO4 -> Na2SO4 + H2O. To balance it, you need to ensure the same number of atoms of each element on both sides of the equation by adjusting the coefficients. In this case, you would need to put a coefficient of 2 in front of NaOH to balance the equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
