To balance the equation K + Br₂ → KBr, you need to make sure the number of atoms of each element is the same on both sides of the equation. To balance this equation, you need to put a coefficient of 2 in front of KBr. This way, you will have 2 potassium atoms, 2 bromine atoms, and 2 KBr molecules on both sides of the equation.
The balanced equation for Cl2 + 2KBr -> 2Br2 + 2KCl is balanced as it conserves the number of atoms on both sides of the reaction. Two moles of KBr reacts with one mole of Cl2 to produce two moles each of Br2 and KCl.
When potassium bromide (KBr) is dissolved in water (H2O), the ions dissociate to form K+ and Br- ions. When elemental bromine (Br2) is added, the Br2 reacts with Br- ions to form bromine molecules (Br2), creating a red-brown color in the solution due to the formation of bromine.
This is a double displacement reaction where bromine (Br2) reacts with potassium iodide (KI) to form potassium bromide (KBr) and iodine (I2) by exchanging ions. The bromine displaces the iodine from potassium iodide to form potassium bromide and free iodine.
The correct chemical equation for the reaction is: Cl2 + 2KBr → 2KCl + Br2. The reaction involves chlorine gas (Cl2) reacting with potassium bromide (KBr) to form potassium chloride (KCl) and bromine gas (Br2).
When potassium bromide (KBr) reacts with chlorine gas (Cl2), it forms potassium chloride (KCl) and bromine (Br2). This reaction is a redox reaction, with bromide ions being oxidized to bromine gas and chlorine being reduced to chloride ions.
2 K + Br2 -> 2 Kbr
The balanced equation for Cl2 + 2KBr -> 2Br2 + 2KCl is balanced as it conserves the number of atoms on both sides of the reaction. Two moles of KBr reacts with one mole of Cl2 to produce two moles each of Br2 and KCl.
No, the chemical equation K + Br2 → 2KBr is balanced in terms of atoms but not charges. To balance it completely, you need to ensure that the charges are equal on both sides of the reaction.
When potassium bromide (KBr) is dissolved in water (H2O), the ions dissociate to form K+ and Br- ions. When elemental bromine (Br2) is added, the Br2 reacts with Br- ions to form bromine molecules (Br2), creating a red-brown color in the solution due to the formation of bromine.
This is a double displacement reaction where bromine (Br2) reacts with potassium iodide (KI) to form potassium bromide (KBr) and iodine (I2) by exchanging ions. The bromine displaces the iodine from potassium iodide to form potassium bromide and free iodine.
The correct chemical equation for the reaction is: Cl2 + 2KBr → 2KCl + Br2. The reaction involves chlorine gas (Cl2) reacting with potassium bromide (KBr) to form potassium chloride (KCl) and bromine gas (Br2).
When potassium bromide (KBr) reacts with chlorine gas (Cl2), it forms potassium chloride (KCl) and bromine (Br2). This reaction is a redox reaction, with bromide ions being oxidized to bromine gas and chlorine being reduced to chloride ions.
The reaction 2KBr → 2K + Br2 is endothermic because heat must be supplied to break the bonds in potassium bromide (KBr) in order to form potassium (K) and bromine gas (Br2).
Potassium plus bromine will react to form potassium bromide, which is a white crystalline compound commonly used in various applications such as in photography, pharmaceuticals, and as a flame retardant.
KCl: 2K(s) + Cl2(g) -> 2KCl(s) Br2: Br2(l) -> 2Br(s)
cl2 kbr---kcl br2i think u mean balance it right ^^;here u have cl2 kbr---kcl br2 so what u do iscl2 kbr---kcl br2cl=2 cl=1k=1 k=1br=1 br=2so u need to balance that ...u need to add (2) to kbr and add (2) to kcl so that u have Cl2 (2)KBr ----(2)KCl Br2 hope that will help ^^ so now u have them balanced by adding 2 in front of kbr that means u r multiplying them by 2 so that K is going to be k=2 and br is going to be br=2 and u r doing that because there is br =1 on one side and the other side there is br=2 and u need them balanced. By adding 2 to kcl means that the other k now is k=2 so as cl. hope its helpful ^____~
KBrO3 and KBr do not react with each other because they have same cation K+, but separately they react with H2SO4. 2KBrO3 + H2SO4 -------> K2SO4 + 2HBrO3 2KBr + H2SO4 ----------> K2SO4 + 2HBr