To balance the equation Fe + O2 -> Fe3O4, you need to make sure that the number of each type of atom on both sides of the equation is the same. In this case, you can balance the equation by placing a coefficient of 4 in front of Fe on the left side and a coefficient of 3 in front of O2 on the right side. This will give you the balanced equation: 4Fe + 3O2 -> 2Fe3O4.
To balance the equation Fe + H2O → Fe3O4 + H2, you need to ensure the number of atoms of each element are equal on both sides. Start by balancing the iron atoms, then balance the oxygen atoms, and finally balance the hydrogen atoms. The balanced equation is 3Fe + 4H2O → Fe3O4 + 4H2.
To calculate the moles of iron (Fe) in 100.0 kg of Fe3O4, you first need to determine the molar mass of Fe3O4, which is 231.54 g/mol. Then convert 100.0 kg to grams (100,000 g), and divide by the molar mass to find the moles of Fe3O4. Since there is 3 moles of Fe for every 1 mole of Fe3O4, you would have 3 times the number of moles of Fe.
The balanced equation is 8Fe3O4 + 4Al → 4Al2O3 + 9Fe. The coefficient of Fe is 9.
The oxidation number of Fe in Fe2O3 (iron(III) oxide) is +3. Each oxygen atom is assigned an oxidation number of -2, and since the overall compound is neutral, the oxidation number of Fe must be +3 to balance the charges.
Fe3O4 has a total of 7 atoms, with 3 iron atoms (Fe) and 4 oxygen atoms (O).
To balance the equation Fe + H2O → Fe3O4 + H2, you need to ensure the number of atoms of each element are equal on both sides. Start by balancing the iron atoms, then balance the oxygen atoms, and finally balance the hydrogen atoms. The balanced equation is 3Fe + 4H2O → Fe3O4 + 4H2.
The balanced equation is: 3Fe + 4H2O → Fe3O4 + 4H2. To balance it, you need to ensure that the number of atoms of each element is the same on both sides of the equation. In this case, you adjust the coefficients to get the same number of atoms of Fe, H, and O on both sides.
To calculate the moles of iron (Fe) in 100.0 kg of Fe3O4, you first need to determine the molar mass of Fe3O4, which is 231.54 g/mol. Then convert 100.0 kg to grams (100,000 g), and divide by the molar mass to find the moles of Fe3O4. Since there is 3 moles of Fe for every 1 mole of Fe3O4, you would have 3 times the number of moles of Fe.
A combustion reaction. It's not a combustion reaction, it's a COMBINATION reaction Example 3 Fe + 2 O2 ----------> Fe3O4
The balanced equation is 8Fe3O4 + 4Al → 4Al2O3 + 9Fe. The coefficient of Fe is 9.
4 Fe+ 3O2 + 6 H2O 4 Fe(OH)3 2 Fe2O3 + (x)H2OThis means that water doesn't actually react, but is necessary to perform the reaction and comes out as it is.
The oxidation number of Fe in Fe2O3 (iron(III) oxide) is +3. Each oxygen atom is assigned an oxidation number of -2, and since the overall compound is neutral, the oxidation number of Fe must be +3 to balance the charges.
Fe3O4 has a total of 7 atoms, with 3 iron atoms (Fe) and 4 oxygen atoms (O).
The balance equation would be 4Fe + 3O2 ==> 2Fe2O3, so the coefficients are 4, 3, 2.
In Fe3O4, the oxidation number of Fe is +8/3. This can be found by setting up an equation where the total sum of the oxidation numbers in the compound equals the overall charge. In this case, Fe3O4 has a neutral charge, so the total sum of oxidation numbers is zero.
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
Fe ions =,Fe 2+andFe 3+Oxygen ions =,O 2-So, as you should see, Fe3O4, is an invalid species as the charge on the first iron ion would be 3 * 2+ = 6 +, and the charge on the second iron ion would be 3 * 3+ = 9+. This can not equal 4 * 2- = 8 -.