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First you must determine whether the bond is ionic, polar, or covalent.

You can do this by looking at the legend on a Periodic Table for where/how the indicate the electro negativity of a element (EN). Find this for both elements involves with the bond, and subtract the two from each other.

This gives you the difference of EN.

Ex. En of Phosphorus = 2.1

En of Oxygen = 3.5

Difference of EN = 3.5 - 2.1

= 1.4

Now you must use the Difference of EN to classify the bond.

If it is less than 0.5, the bond is covalent, and will not have poles

(it shares electrons, meaning it has no polarity)

If it is greater than 1.7, it is ionic, and in this case, whichever element has

the positive ion (the element the electron(s) move to (always a non-metal))

is the south or negative pole. The one that looses the electron(s) (always a

metal) in the bond is the north or positive pole.

If it is between 0.5 and 1.7 then it is polar, and it will have a partial charge

(meaning one of the atoms attracts/hogs the electrons). In this case, the

element with the higher EN is the south or negative poll, and the other is

the north or positive poll.

In Summary:

Step 1, Find the EN of both elements

Step 2, Calculate the Difference of EN

Step 3, Determine the type of bond (covalent, ionic, or polar)

Step 4, Determine which end has more electrons (that end will have a negative

charge and therefore be the south poll)

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10y ago
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5mo ago

You can find the polarity of a chemical bond by comparing the electronegativities of the atoms involved. If there is a significant difference in electronegativity, the bond is polar. The atom with higher electronegativity attracts electrons more strongly, resulting in a partial negative charge on that atom and a partial positive charge on the other atom.

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Q: How can you find the polarity of a chemical bond?
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