This may best be demonstrated by example:
Here are two forms (read: oxidation numbers) of iron, as FeO and Fe2O3. Because we know oxygen has a -2 charge per atom, the oxidation number of Fe in FeO is II. As for Fe2O3, we know that the oxidation number of Fe is III; there is no charge on the compound, so the two iron molecules must equally offset the -6 charge from the three oxygen atoms.
Oxidation numbers are written as roman numerals. You would write these two forms of iron oxide as iron(II) oxide and iron(III) oxide, respectively. Oxidation states are the (+) or (-) charges written as a superscript.
The oxidation number of an element is determined based on the number of electrons it gains or loses in a chemical reaction. It is used to track the flow of electrons in a reaction, identify the element that is oxidized or reduced, and balance chemical equations. Oxidation numbers help in determining the overall charge of a compound and in predicting the reactivity of elements.
The oxidation number of PH4 cannot be determined because phosphorus (P) does not have a fixed oxidation number in this compound.
In ionic compounds, the oxidation number is determined by the charge associated with each ion. For cations, the oxidation number is the same as the charge on the ion. For anions, the oxidation number is the negative of the charge on the ion. The sum of the oxidation numbers in an ionic compound must be zero.
The oxidation number of Mn in KMnO4 is +7. This can be determined by assigning the known oxidation numbers of potassium (+1) and oxygen (-2) and solving for the unknown oxidation number of manganese.
The oxidation number of B in B4O7 is +3. This can be determined by assigning oxygen an oxidation number of -2, then setting up an equation to solve for the oxidation number of B.
The oxidation number of Phosphorus (P) in H3P2O7 is +5. This can be determined by assigning hydrogen an oxidation number of +1 and oxygen an oxidation number of -2, then setting up an equation to solve for the unknown oxidation number of Phosphorus.
The oxidation number of PH4 cannot be determined because phosphorus (P) does not have a fixed oxidation number in this compound.
In ionic compounds, the oxidation number is determined by the charge associated with each ion. For cations, the oxidation number is the same as the charge on the ion. For anions, the oxidation number is the negative of the charge on the ion. The sum of the oxidation numbers in an ionic compound must be zero.
The oxidation number of Mn in KMnO4 is +7. This can be determined by assigning the known oxidation numbers of potassium (+1) and oxygen (-2) and solving for the unknown oxidation number of manganese.
The oxidation number of B in B4O7 is +3. This can be determined by assigning oxygen an oxidation number of -2, then setting up an equation to solve for the oxidation number of B.
The oxidation number of Phosphorus (P) in H3P2O7 is +5. This can be determined by assigning hydrogen an oxidation number of +1 and oxygen an oxidation number of -2, then setting up an equation to solve for the unknown oxidation number of Phosphorus.
The oxidation number of copper (Cu) in CuCO3 is +2. Oxygen typically has an oxidation number of -2, and the overall charge of the carbonate ion (CO3) is -2. Therefore, the oxidation number of copper is determined to be +2 in this compound.
The oxidation number of sulfur in MnSO4 is +6. This can be determined by considering the oxidation number of manganese as +2 and the overall charge of the compound as neutral.
The oxidation number of an atom in a molecule of water (H2O) is determined based on the electronegativity of the atoms involved. In water, oxygen typically has an oxidation number of -2, while each hydrogen atom has an oxidation number of +1.
The oxidation number for iodine in iodine pentoxide (I2O5) is +5. This is determined by taking into account the overall charge of the compound and the known oxidation number of oxygen atoms in a molecule.
The oxidation number of Mn in MnO4- is +7. This is determined by balancing the charge of the whole ion (-1) with the charges of the oxygen atoms (-8) and solving for the oxidation number of Mn.
In Fe2O3, iron (Fe) has an oxidation number of +3, and oxygen (O) has an oxidation number of -2. Iron's oxidation number is determined by balancing the overall charge of the compound based on the known oxidation number of oxygen.
In MnCo2, Mn has an oxidation number of +2, and Co has an oxidation number of -1. This is determined by assigning oxidation numbers based on rules for assigning oxidation numbers to each element in the compound.