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How can one determine if a molecule is polar or nonpolar without relying on electronegativity values?
One way to determine if a molecule is polar or nonpolar without relying on electronegativity values is to consider its molecular geometry. If a molecule has a symmetrical shape and the individual bond dipoles cancel each other out, then the molecule is nonpolar. On the other hand, if the molecule has an asymmetrical shape and the bond dipoles do not cancel out, then the molecule is polar.
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How can one determine if a bond is polar or nonpolar without relying on electronegativity?
One can determine if a bond is polar or nonpolar by looking at the symmetry of the molecule. If the molecule is symmetrical and the atoms on either side of the bond are the same, the bond is likely nonpolar. If the molecule is asymmetrical or the atoms on either side of the bond are different, the bond is likely polar.
How can one determine polarity in a molecule without relying on electronegativity values?
One can determine polarity in a molecule by looking at its molecular geometry and the distribution of its electron density. If the molecule has an uneven distribution of electrons, it is likely to be polar. This can be determined by examining the symmetry of the molecule and the presence of any polar bonds.
Is I3- polar or non-polar?
its T-shaped, So if we take the vectors of the right and left side , both of them will cancel ,eventually you will be left out with the downward vector which wont cancel. So the sum will be >0therefore, Its Polar
How can one determine if a reaction is endothermic or exothermic without relying on enthalpy values?
One way to determine if a reaction is endothermic or exothermic without using enthalpy values is by observing the temperature change during the reaction. If the temperature increases, the reaction is likely exothermic, releasing heat. If the temperature decreases, the reaction is likely endothermic, absorbing heat.
For which of the following molecules would the intermolecular forces be due mainly to London forces CH3COCH3 O2 CH3OH SO3 H2S?
The intermolecular forces for O2 and H2S would be mainly due to London dispersion forces since they have only nonpolar covalent bonds. CH3OH and SO3 would have additional intermolecular forces due to hydrogen bonding and dipole-dipole interactions. CH3COCH3 would have dipole-dipole interactions as well as London dispersion forces.
