Gold and platinum will no react with HNO3 due to their low reactivity. Aluminum also will not react with HNO3 despite its relatively high reactivity because it has a protective layer of aluminum oxide on it.
HNO3 and Ca(OH)2 react to form calcium nitrate [Ca(NO3)2] and water [H2O].
To find the volume of 16M HNO3 required to react with 0.0214g of Cu metal, you need to calculate the moles of Cu. Then, using the balanced equation for the reaction between Cu and HNO3 (Cu + 4HNO3 β Cu(NO3)2 + 2NO2 + 2H2O), you can determine the moles of HNO3 needed. Finally, using the molarity of the HNO3 solution, you can calculate the volume in drops.
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
Yes, sulfur can react with dilute nitric acid (HNO3) to form sulfur dioxide gas, nitrogen dioxide gas, and water. This reaction is a redox reaction where sulfur is oxidized and nitric acid is reduced.
No. HNO3 already has hydrogen and nitrogen in their highest possible oxidation states.
Gold and platinum will no react with HNO3 due to their low reactivity. Aluminum also will not react with HNO3 despite its relatively high reactivity because it has a protective layer of aluminum oxide on it.
The balanced chemical equation for the reaction between copper (Cu) and nitric acid (HNO3) is: 3Cu + 8HNO3 -> 3Cu(NO3)2 + 2NO + 4H2O According to the equation, 8 moles of HNO3 are required to react with 3 moles of Cu. Therefore, to react with 6 moles of Cu, you would need 16 moles of HNO3.
HNO3 and Ca(OH)2 react to form calcium nitrate [Ca(NO3)2] and water [H2O].
When AlCl3 reacts with HNO3, the products are Al(NO3)3 and HCl. When AlCl3 reacts with AgNO3, the products are AgCl and Al(NO3)3.
To find the volume of 16M HNO3 required to react with 0.0214g of Cu metal, you need to calculate the moles of Cu. Then, using the balanced equation for the reaction between Cu and HNO3 (Cu + 4HNO3 β Cu(NO3)2 + 2NO2 + 2H2O), you can determine the moles of HNO3 needed. Finally, using the molarity of the HNO3 solution, you can calculate the volume in drops.
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
Yes, sulfur can react with dilute nitric acid (HNO3) to form sulfur dioxide gas, nitrogen dioxide gas, and water. This reaction is a redox reaction where sulfur is oxidized and nitric acid is reduced.
The balanced molecular equation for the reaction between sodium sulfide (Na2S) and potassium iodide (KI) is: 2Na2S + 2KI -> 2NaI + K2S.
Na2S
To find out how many atoms of zinc react with 1.49 g of HNO3, you would first need to balance the chemical equation for the reaction. Then, you can convert the mass of HNO3 to moles using its molar mass. Finally, use the coefficients in the balanced equation to determine the mole ratio between zinc and HNO3 to find the number of atoms of zinc involved in the reaction.
NaHCl + HNO3 --> H2 + NaNO2 + ClO