To calculate the percent yield, you need to know the amount of copper oxide formed and compare it to the theoretical yield. The theoretical yield can be calculated based on the initial amount of copper, assuming complete conversion. Once you have both values, use the formula: Percent Yield = (Actual Yield / Theoretical Yield) x 100.
To calculate the percentage yield of copper (II) sulfate pentahydrate, you would divide the actual yield of the compound by the theoretical yield, and then multiply by 100 to get the percentage. The theoretical yield can be calculated based on the stoichiometry of the reaction and the amount of reactant used, while the actual yield is determined through experimentation.
Cu + 2H2SO4 -> CuSO4 + 2H2O + SO2
Yes, sodium carbonate (Na2CO3) will react with sulfuric acid (H2SO4) to form sodium sulfate (Na2SO4), carbon dioxide (CO2) gas, and water (H2O).
The theoretical yield of ammonium sulfate can be calculated based on the amount of ammonia used. To find the percent yield, divide the actual yield (985 g) by the theoretical yield and multiply by 100. Percent yield = (actual yield / theoretical yield) x 100.
Strontium chloride and sodium sulfate will react to form strontium sulfate and sodium chloride. This reaction is a double displacement reaction where the cations and anions of the two compounds switch partners.
To calculate the percent yield, you need to know the amount of copper oxide formed and compare it to the theoretical yield. The theoretical yield can be calculated based on the initial amount of copper, assuming complete conversion. Once you have both values, use the formula: Percent Yield = (Actual Yield / Theoretical Yield) x 100.
To calculate the percentage yield of copper (II) sulfate pentahydrate, you would divide the actual yield of the compound by the theoretical yield, and then multiply by 100 to get the percentage. The theoretical yield can be calculated based on the stoichiometry of the reaction and the amount of reactant used, while the actual yield is determined through experimentation.
Cu + 2H2SO4 -> CuSO4 + 2H2O + SO2
Yes, sodium carbonate (Na2CO3) will react with sulfuric acid (H2SO4) to form sodium sulfate (Na2SO4), carbon dioxide (CO2) gas, and water (H2O).
We'll assume you mean Copper (II) Carbonate - CuCO3CuCO3 + 2 HCl --> CuCl2 + H2O + CO2It forms Copper (II) Chloride, carbon dioxide and water.
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When copper(II) sulfate (CuSO4) and ammonium chloride (NH4Cl) are dissolved in water, they will dissociate into their respective ions. Copper(II) sulfate will yield Cu^2+ and SO4^2- ions, while ammonium chloride will yield NH4^+ and Cl- ions. The ions will remain separate in the solution unless a chemical reaction occurs.
The theoretical yield of ammonium sulfate can be calculated based on the amount of ammonia used. To find the percent yield, divide the actual yield (985 g) by the theoretical yield and multiply by 100. Percent yield = (actual yield / theoretical yield) x 100.
The theoretical yield of ammonium sulfate can be calculated by determining the amount that would be produced if all the ammonia reacted. Given that 500g of ammonia was used, convert this amount to grams of ammonium sulfate. Then, divide the actual yield (1789g) by the theoretical yield and multiply by 100 to calculate the percent yield.
Mixing hydrochloric acid with sodium hydroxide to form salt and water. Combining sulfuric acid with calcium hydroxide to produce calcium sulfate and water. Reacting nitric acid with potassium hydroxide to yield potassium nitrate and water. Mixing acetic acid with ammonia to form ammonium acetate and water. Combining phosphoric acid with barium hydroxide to produce barium phosphate and water. Reacting citric acid with sodium bicarbonate to yield sodium citrate and water. Mixing hydrofluoric acid with sodium carbonate to form sodium fluoride and water. Combining carbonic acid with potassium hydroxide to produce potassium carbonate and water. Reacting oxalic acid with calcium hydroxide to yield calcium oxalate and water. Mixing hydrobromic acid with magnesium hydroxide to form magnesium bromide and water.
3CuCl2 (aq)+ 2Na3PO4 (aq)> 6Na+ (aq)+ 6Cl- (aq)+ Cu3(PO4)2 (s) Or, 3 moles of copper (II) chloride and 2 moles of sodium phosphate form 6 moles of sodium ions, 6 moles of chloride ions, and a mole of copper (II) phosphate, which is insoluble, and precipitates out of the solution.