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Reverse the equation for the decomposition given since you are doing formation. This makes -5678 positive.

Lookup the enthalpy of formation of gaseous water and carbon dioxide and multiply them by their moles in the formation equation. Remember nitrogen is in base form, so it is 0. You want:

Delta H of Reaction = Sum of Prod - Sum of Reactants

5678 = X - [-2418 + 0 + -4722 ]

X = -1462

-1462/4 = -365.5

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10y ago
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6mo ago

The standard enthalpy of formation for nitroglycerin is approximately -364 kJ/mol.

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16y ago

DH= -5288.6 kJ/mol as per the CRC chem & physics handbook.

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16y ago

-5156.95kJ/mol

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12y ago

19.9 kJ/mo;e

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12y ago

20.3+-0.9 kj/mol

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10y ago

1.72 kJ/kg.K

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13y ago

76 kJ

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15y ago

76 kJ

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Q: Calculate the standard enthalpy of formation for nitroglycerin?
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Calculate standard enthalpy of formation of FeO?

You shouldn't "calculate" a standard enthalpy of formation. The beauty of standard enthalpies of formation is that they are already calculated for you. That is why they are delineated by the term "standard" - they are standards that were figured out by chemists some time ago, that never change, and can be found in tables usually in textbooks and even on Wikipedia. If you need to know the standard enthalpy of formation of FeO, Google it. And let me know what you find...because I can't seem to find a set answer either. I have found one site that lists the standard enthalpy of formation of FeO to be 271.9 kJ/mol. But it hasn't been so evident in other places. No wonder you were confused! Good luck.


What is the standard enthalpy for sodium sulfate?

The standard enthalpy of formation for sodium sulfate is -1385.2 kJ/mol.


What is a standard formation reaction?

A standard formation reaction is a chemical reaction in which one mole of a compound is formed from its elements in their standard states (usually at 25°C and 1 atm). It is used to calculate the standard enthalpy of formation of a compound, which is the change in enthalpy when one mole of the compound is formed from its elements.


What is the difference of enthalpy of formation and the enthalpy of combustion?

The enthalpy of formation is the change in enthalpy that occurs when 1 mole of a compound is formed from its elements in their standard states. The enthalpy of combustion is the change in enthalpy that occurs when 1 mole of a substance is completely burned in oxygen. In short, enthalpy of formation is for the formation of a compound, while enthalpy of combustion is for the complete burning of a substance.


What is the basic difference between enthalpy of formation?

The enthalpy of formation refers to the energy change when one mole of a compound is formed from its elements in their standard states, while the standard enthalpy of formation refers to the enthalpy change under standard conditions (usually at 25°C and 1 atm pressure). The enthalpy of formation is specific to the compound being formed, whereas the standard enthalpy of formation allows for comparison between different compounds.

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Calculate standard enthalpy of formation of FeO?

You shouldn't "calculate" a standard enthalpy of formation. The beauty of standard enthalpies of formation is that they are already calculated for you. That is why they are delineated by the term "standard" - they are standards that were figured out by chemists some time ago, that never change, and can be found in tables usually in textbooks and even on Wikipedia. If you need to know the standard enthalpy of formation of FeO, Google it. And let me know what you find...because I can't seem to find a set answer either. I have found one site that lists the standard enthalpy of formation of FeO to be 271.9 kJ/mol. But it hasn't been so evident in other places. No wonder you were confused! Good luck.


Why does oxygen gas not have an enthalpy of formation but ozone does?

Oxygen gas (O2) does not have an enthalpy of formation because it is an element in its standard state, which has an enthalpy of formation of zero by definition. Ozone (O3), on the other hand, is a compound and has a defined enthalpy of formation because it is formed from its elements in their standard states.


What is the standard enthalpy for sodium sulfate?

The standard enthalpy of formation for sodium sulfate is -1385.2 kJ/mol.


What is a standard formation reaction?

A standard formation reaction is a chemical reaction in which one mole of a compound is formed from its elements in their standard states (usually at 25°C and 1 atm). It is used to calculate the standard enthalpy of formation of a compound, which is the change in enthalpy when one mole of the compound is formed from its elements.


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What is the difference of enthalpy of formation and the enthalpy of combustion?

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What is the basic difference between enthalpy of formation?

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