Reverse the equation for the decomposition given since you are doing formation. This makes -5678 positive.
Lookup the enthalpy of formation of gaseous water and carbon dioxide and multiply them by their moles in the formation equation. Remember nitrogen is in base form, so it is 0. You want:
Delta H of Reaction = Sum of Prod - Sum of Reactants
5678 = X - [-2418 + 0 + -4722 ]
X = -1462
-1462/4 = -365.5
You shouldn't "calculate" a standard enthalpy of formation. The beauty of standard enthalpies of formation is that they are already calculated for you. That is why they are delineated by the term "standard" - they are standards that were figured out by chemists some time ago, that never change, and can be found in tables usually in textbooks and even on Wikipedia. If you need to know the standard enthalpy of formation of FeO, Google it. And let me know what you find...because I can't seem to find a set answer either. I have found one site that lists the standard enthalpy of formation of FeO to be 271.9 kJ/mol. But it hasn't been so evident in other places. No wonder you were confused! Good luck.
The standard enthalpy of formation for sodium sulfate is -1385.2 kJ/mol.
A standard formation reaction is a chemical reaction in which one mole of a compound is formed from its elements in their standard states (usually at 25°C and 1 atm). It is used to calculate the standard enthalpy of formation of a compound, which is the change in enthalpy when one mole of the compound is formed from its elements.
The enthalpy of formation is the change in enthalpy that occurs when 1 mole of a compound is formed from its elements in their standard states. The enthalpy of combustion is the change in enthalpy that occurs when 1 mole of a substance is completely burned in oxygen. In short, enthalpy of formation is for the formation of a compound, while enthalpy of combustion is for the complete burning of a substance.
The enthalpy of formation refers to the energy change when one mole of a compound is formed from its elements in their standard states, while the standard enthalpy of formation refers to the enthalpy change under standard conditions (usually at 25°C and 1 atm pressure). The enthalpy of formation is specific to the compound being formed, whereas the standard enthalpy of formation allows for comparison between different compounds.
You shouldn't "calculate" a standard enthalpy of formation. The beauty of standard enthalpies of formation is that they are already calculated for you. That is why they are delineated by the term "standard" - they are standards that were figured out by chemists some time ago, that never change, and can be found in tables usually in textbooks and even on Wikipedia. If you need to know the standard enthalpy of formation of FeO, Google it. And let me know what you find...because I can't seem to find a set answer either. I have found one site that lists the standard enthalpy of formation of FeO to be 271.9 kJ/mol. But it hasn't been so evident in other places. No wonder you were confused! Good luck.
Oxygen gas (O2) does not have an enthalpy of formation because it is an element in its standard state, which has an enthalpy of formation of zero by definition. Ozone (O3), on the other hand, is a compound and has a defined enthalpy of formation because it is formed from its elements in their standard states.
The standard enthalpy of formation for sodium sulfate is -1385.2 kJ/mol.
A standard formation reaction is a chemical reaction in which one mole of a compound is formed from its elements in their standard states (usually at 25°C and 1 atm). It is used to calculate the standard enthalpy of formation of a compound, which is the change in enthalpy when one mole of the compound is formed from its elements.
The standard enthalpy of formation of coconut oil is not a well-defined value as it is a complex mixture of triglycerides, which are composed of various fatty acids. The enthalpy of formation of each individual fatty acid can be determined, but not for coconut oil as a whole.
The enthalpy of formation is the change in enthalpy that occurs when 1 mole of a compound is formed from its elements in their standard states. The enthalpy of combustion is the change in enthalpy that occurs when 1 mole of a substance is completely burned in oxygen. In short, enthalpy of formation is for the formation of a compound, while enthalpy of combustion is for the complete burning of a substance.
The standard enthalpies of formation provide a reference point for measuring the amount of heat released or absorbed during a chemical reaction. By defining these values, scientists can calculate the overall enthalpy change for a reaction, which helps in predicting reaction spontaneity and equilibrium conditions.
The enthalpy of formation refers to the energy change when one mole of a compound is formed from its elements in their standard states, while the standard enthalpy of formation refers to the enthalpy change under standard conditions (usually at 25°C and 1 atm pressure). The enthalpy of formation is specific to the compound being formed, whereas the standard enthalpy of formation allows for comparison between different compounds.
The standard enthalpy of formation for potassium hydroxide is -425,8 kJ/mol.
The balanced chemical equation is: CO2(g) + 2KOH(s) -> H2O(g) + K2CO3(s). The enthalpy change (ΔHrxn) for this reaction is the enthalpy of formation of the products minus the enthalpy of formation of the reactants. To calculate it, you would need the standard enthalpies of formation for all species involved.
The enthalpy of formation (ΔHf) is the heat associated with the formation of one mole of a compound from its elements in their standard states. It represents the energy change when the compound is formed from its constituent elements under standard conditions.
The standard enthalpy of formation for NaCl solid is: -411,12 kJ/mol at 25 0C.