Water (H2O) does not spontaneously break down into hydrogen (H2) and oxygen (O2) at a specific temperature. Instead, water can be broken down into hydrogen and oxygen gas through a process called electrolysis, which involves passing an electric current through water to separate the hydrogen and oxygen molecules.
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
The balanced chemical equation for the reaction is 2H2 + O2 -> 2H2O. Using stoichiometry, we find that 3g of H2 will react completely with 24g of O2 to form 18g of H2O. Therefore, the maximum amount of H2O formed when 3g of H2 reacts with 29g of O2 is 18g.
The equation for the reaction of hydrogen gas (H2) and oxygen gas (O2) to form water (H2O) is: 2H2 + O2 -> 2H2O. This reaction is commonly known as the combustion of hydrogen.
The reaction 2 H2O β 2 H2 + O2 is a decomposition reaction, where a compound (water) breaks down into two or more simpler substances (hydrogen and oxygen).
The chemical equation for the gasification of coal can be represented as: C + H2O -> CO + H2
= H2+O2 =2H2+O2=2H2O
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
The reactants in this equation are hydrogen gas (H2) and oxygen gas (O2).
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
This simple equation is: 2H2 + O2 = 2H2O
The balanced chemical equation for the reaction is 2H2 + O2 -> 2H2O. Using stoichiometry, we find that 3g of H2 will react completely with 24g of O2 to form 18g of H2O. Therefore, the maximum amount of H2O formed when 3g of H2 reacts with 29g of O2 is 18g.
It is not balanced. There should be a 2 in front of H2 and H2O
H2 +o2 --->h2o
H2 +o2 --->h2o
The equation for the reaction of hydrogen gas (H2) and oxygen gas (O2) to form water (H2O) is: 2H2 + O2 -> 2H2O. This reaction is commonly known as the combustion of hydrogen.
The reaction 2 H2O β 2 H2 + O2 is a decomposition reaction, where a compound (water) breaks down into two or more simpler substances (hydrogen and oxygen).
its doesnot seems practical but we can hypothetically say that, by dissociating H2O molecule to H2 and O2 by hydrolysis can act as fuel because h2 is combustable and O2 supports combution.