19,5 g butane are needed.
The unbalanced combustion reaction of C4H10(g) with O2(g) produces CO2(g) and H2O(g) as products. The balanced reaction is: C4H10(g) + O2(g) → CO2(g) + H2O(g)
The complete combustion of 2,2-dimethylpropane (C4H10) in oxygen produces carbon dioxide (CO2) and water (H2O) as the only products. The balanced chemical equation for this reaction is: C4H10 + 6O2 → 4CO2 + 5H2O
To produce 20 ml of water, you would need 22.2 ml of C4H10. This is calculated using the balanced chemical equation for the combustion of C4H10, which shows that for every mole of C4H10 combusted, you get 6 moles of water.
The combustion of Butane (C4H10) with oxygen (02) produces carbon dioxide (CO2) and water (H2O). The balanced and simplified this reaction is 2 butane + 13 water = 8 carbon dioxide and 10 water.
The balanced chemical equation for the combustion of butane (C4H10) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O
19,5 g butane are needed.
The unbalanced combustion reaction of C4H10(g) with O2(g) produces CO2(g) and H2O(g) as products. The balanced reaction is: C4H10(g) + O2(g) → CO2(g) + H2O(g)
The balanced equation for the reaction of tetracarbon decahydride (C4H10) and oxygen (O2) is: C4H10 + 6.5 O2 → 4 CO2 + 5 H2O.
This chemical equation is unbalanced. To balance it, start by balancing the carbons, then hydrogens, and finally oxygens. The balanced equation is: C4H10 + 6.5 O2 -> 4 CO2 + 5 H2O.
The complete combustion of 2,2-dimethylpropane (C4H10) in oxygen produces carbon dioxide (CO2) and water (H2O) as the only products. The balanced chemical equation for this reaction is: C4H10 + 6O2 → 4CO2 + 5H2O
The balanced equation for the combustion of butane (C4H10) in oxygen (O2) to form carbon dioxide (CO2) and water vapor (H2O) is: 2C4H10 + 13O2 -> 8CO2 + 10H2O.
2c4h10 + 13o2 => 8co2 + 10h2o (I am having some trouble with my typography today, but all those letters above should be capitalized.)
To produce 20 ml of water, you would need 22.2 ml of C4H10. This is calculated using the balanced chemical equation for the combustion of C4H10, which shows that for every mole of C4H10 combusted, you get 6 moles of water.
Partial answer:CxHy is used to indicate a generic hydrocarbon fuel.A specific hydrocarbon would be, for example, C4H10. That is the molecular formula for Butane.
The combustion of Butane (C4H10) with oxygen (02) produces carbon dioxide (CO2) and water (H2O). The balanced and simplified this reaction is 2 butane + 13 water = 8 carbon dioxide and 10 water.
Incomplete combustion of the butane. Which means that there is a lack of oxygen getting into the system. C4H10 + 4½O2 -> 4CO + 5H2O In excess O2 only CO2 and H2O are produced. C4H10 + 6½O2 -> 4CO2 + 5H2O