The reactants are methane CH4 and oxygen O2
and the products are carbon dioxide CO2 and water H2O.
CH4 + 2 O2 --> CO2 + 2 H2O
The balanced chemical equation for methane (CH4) burning in air (O2) is: CH4 + 2O2 → CO2 + 2H2O
The word equation for the burning of octane in air is: octane + oxygen -> carbon dioxide + water.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that the mole ratio of air to methane gas is 2:1, as two moles of oxygen from the air are required to react with one mole of methane gas.
The word equation is magnesium + oxygen(air) = magnesium oxide. The Balanced chemical eq'n is 2Mg(s) + O2(g) = 2MgO(s)
The word equation for the reaction between sulfur and air is: sulfur + oxygen → sulfur dioxide.
The balanced chemical equation for methane (CH4) burning in air (O2) is: CH4 + 2O2 → CO2 + 2H2O
The word equation for a candle burning in the air is: Wax + Oxygen → Carbon Dioxide + Water + Light + Heat.
Ca+O=CaO
No it is not essential. It will burn in air or oxygen if ignited by some spark or match but there are many other ways to get burning in chemistry. The requirements for burning are fuel, oxygen and heat. Oxygen can be supplied by the air for many fires. Heat must often be introduced initially to ignite the fuel but the heat of combustion will then be enough to sustain the burning. Fuel could be methane but there are many other potential fuels in chemistry, for example hydrogen, propane, wood ... Many dry foodstuffs will burn in air if lit.
4K(s) + O2(g) --> 2K2O
We can stop burning methane. Actually burning methane is better than letting it escape into the atmosphere. Methane, when burnt, emits carbon dioxide, a powerful greenhouse gas, but methane, when released into the air, is twenty-one times more dangerous.
The word equation for the burning of octane in air is: octane + oxygen -> carbon dioxide + water.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that the mole ratio of air to methane gas is 2:1, as two moles of oxygen from the air are required to react with one mole of methane gas.
The balanced chemical equation for burning C18H38 in air is: 2C18H38 + 55O2 → 36CO2 + 38H2O
ethanol + oxygen ----> Carbon Dioxide + water (assume complete combustion) CH3CH2OH + 3O2 ---> 2CO2 + 3H2O *also, when a compound is burning,we chemists use the term Combustion, which refers to the exothermic reactions which occur between some fuel source and an oxidant. Thus, "Ethanol burning in air" is rather redundant :]
Sodium particularly reacts with the Oxygen in the Air while burning. Sodium + Oxygen ----> Sodium oxide
The word equation is magnesium + oxygen(air) = magnesium oxide. The Balanced chemical eq'n is 2Mg(s) + O2(g) = 2MgO(s)