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∙ 14y ago0.01 mole
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∙ 14y agoSince sodium carbonate dissociates into two sodium ions for every one formula unit, one mole of Na2CO3 will provide 2 equivalents of sodium ions. Therefore, a 0.0100 M solution of sodium carbonate will contain 0.0200 equivalents of sodium ions per liter of the solution.
To determine the pH of sodium carbonate, you can dissolve a known quantity of sodium carbonate in water to create a solution, and then measure the pH of the solution using a pH meter or pH indicator paper. Alternatively, you can calculate the pH of the solution using the dissociation constant of sodium carbonate and the concentration of the solution.
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
The molarity of the solution is calculated by dividing the moles of solute (KCl) by the volume of solution in liters. In this case, molarity = 0.202 mol / 7.98 L ≈ 0.0253 mol/L.
The molarity of the solution is calculated by dividing the moles of solute by the liters of solution. In this case, molarity = 0.202 mol / 7.98 L ≈ 0.0253 M.
The molarity of the solution can be calculated by dividing the number of moles of solute by the volume of the solution in liters. Therefore, the molarity of the solution is 0.400 mol / 9.79 L = 0.041 mol/L.
The molarity is 0,041
The molarity is 0,025.
Upon doing some simple calculations the answer is 2.4 M
If 1,1 is grams the molarity is 0,317.
This molarity is 1,59.
To determine the pH of sodium carbonate, you can dissolve a known quantity of sodium carbonate in water to create a solution, and then measure the pH of the solution using a pH meter or pH indicator paper. Alternatively, you can calculate the pH of the solution using the dissociation constant of sodium carbonate and the concentration of the solution.
The molar mass of KMnO4 is 158,3415 g.The molarity of this solution is 0,1 M.
The molarity is 0.718 moles/litre.
This molarity is 0,207 mol.
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
Molarity is moles of solvent divided by liters of solution, so 6.42 / 1.75 = 3.67M.