It depends upon the weight of the car, the coefficient of friction for the brake linings, and the type of tire and contact with the road surface. A Formula One car can stop in these conditions very quickly. See this link for further explanation: http://www.csgnetwork.com/stopdistinfo.html A calculator can be found here: http://www.Oregon.gov/OSP/PATROL/stop_brake_distance_chart.shtml Using the calculations from this website's downloadable EXCEL sheet shows that a vehicle traveling 197 mph and weighing 4000 pounds would take 1764 feet to stop with a drivers reaction time of .5 seconds considering the coefficient friction value of .8 which would be considered an ABS brake system with excellent tires.
When traveling 30-mph, the braking distance is 45-feet, and the total stopping distance is 75-feet. This is the length of a semi-truck and trailer.
1/2
Stopping Distance = about 315 feet at 70 mph
Yes it will need the stopping distance of a automobile traveling at the same speed and then it will need a few hundred more feet as well.
Stopping distance at 30mph = 23m
Stopping Distance = 15 feet
At 20 mph, the average thinking distance is around 20 feet, while the braking distance is approximately 20 feet as well. Therefore, the overall stopping distance for a vehicle traveling at 20 mph would be around 40 feet.
4.6 meters or 15ft. is the estimated stoping distance of a vehicle travelling at 25 MPH. Thinking time and weather or not you are sober have not been taken into account.
1/2 mile
Stopping Distance = about 146.25 feet.
Stopping distance at 40mph = 36m
h w many feet will it stop in