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At the center, for every particle of mass in the earth to attract you gravitationally,
there's an equal particle with the same mass, located at the same distance from
you in exactly the opposite direction, balancing out the force toward the first one.
All of this is a theoretically ideal case. It assumes that the earth is a perfect sphere,
with the same distribution of mass in every direction from the center. The real earth
is lumpy, oddly shaped, and bumpy, so the acceleration of gravity wouldn't be exactly
zero at the center.
The value of 'g' (acceleration due to gravity) is zero at the center of the Earth because all the mass of the Earth is surrounding that point, causing gravitational forces from all directions to cancel each other out. This results in a net gravitational force of zero at the center.
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Where the gravitational field strength is maximum?
The gravitational field strength is maximum at the surface of a massive object, such as a planet or star. This is because the gravitational force is directly proportional to the mass of the object and inversely proportional to the square of the distance from the center of the object.
How g becomes zero at the centre of earth?
At the center of the Earth, the gravitational force from the mass above you cancels out, resulting in a net gravitational force of zero. This means you would experience weightlessness at the center of the Earth due to the balanced gravitational forces acting in all directions.
What factor affects gravitational force?
a gravitational force is a force of attraction , which attracts the all organisms and things , it also attracts the things in space [universe for where the gravitational field is there] for suppose our earth is a planet which have gravity , a sun[star] have more gravity in solar system. Improved answer: Gravitational force on a body brings the weight of the body. This is given by the expression W = mg. m-the mass of the body. g-the acceleration due to gravity. When this g gets affected then gravitational force varies. g is affected by so many factors. i) the altitu. de as we go away from the centre of the earth, g decreases ii) The depth. As we go towards the centre of the earth once again g decreases iii) Due to rotation of the earth the centrifugal acceleration would decrease the value of g, the most along the equator. iv) g could be proved to be GM/R2. G the universal gravitational constant M-mass of the earth R- radius of the earth. Hence due to non even spherical shape of the earth g value varies v) if a body gets immersed in a liquid then the weight is affected by the buoyant force. So the weight is reduced.
What distance from centre of earth where value of g is half?
You haven't said 'half' of WHAT .I'll assume that you mean "half of what it is on the surface", andI shall now proceed to answer the question that I have invented:(x/earth radius)2 = 2x = (earth radius) times sqrt(2) =9,010 km (5,599 miles) from the center2,639 km (1,640 miles) from the surface(all rounded)
What is earth's gravitational strength?
The gravitational strength on Earth's surface is approximately 9.81 meters per second squared (m/s^2). This value represents the acceleration due to gravity and determines the force that pulls objects towards the center of the Earth.
IS VALUE OF g at centre of the earth maximum?
Yes, the value of the acceleration due to gravity (g) at the center of the Earth would be zero, as all the mass of the Earth would be pulling equally in all directions.
What is the value of G at center of earth?
Zero.
What is the value of g at the centre of earth in detail?
The value of acceleration due to gravity (g) at the center of Earth is theoretically zero. This is because the mass surrounding the center exerts equal gravitational force in all directions, effectively canceling each other out at the center point.
What is the earth's gravity in terms of acceleration?
9.8 m/s2 ---------------------- Yes this is the average value of acceleration due to gravity near by the surface of the earth. As we go higher and higher level this g value decreases and becomes almost negligible. Same way as we go deeper and deeper the g value decreases and at the centre of the earth its value becomes zero.
What is the value of 'g' at center of earth?
The value of acceleration due to gravity 'g' at the center of the Earth is theoretically zero because the mass of the Earth surrounds an object equally in all directions, resulting in a net gravitational force of zero at the center.
What is the value of 'g' if the earth stops rotating?
If the Earth were to stop rotating, the value of 'g' (acceleration due to gravity) would remain approximately the same at the Earth's surface. The rotation of the Earth does not significantly affect the gravitational pull experienced on the surface.
What will happen to the value of g if the compound pendulum is taken nearer to the centre of earth?
The value of g would increase if the compound pendulum is taken nearer to the center of the Earth. This is because gravity is stronger closer to the Earth's surface. Conversely, if the compound pendulum is moved further away from the center of the Earth, the value of g would decrease.
What is the acceleration due to gravity at the center of the earth?
g = 9.81 m/s2 = 32.2 ft/s2the above is a wrong answer. that's g on the surface of the earth.g varies and actually decreases as we move up or down the surface. g at the centre of any spherical body due to it's own mass is 0. So g at the centre of earth is zero.
What will be the time period of a simple pendulum at the centre of Earth?
The time period of a simple pendulum at the center of Earth would be ∞ (infinity). This is because the gravitational force is acting equally in all directions and there would be no net force to cause the pendulum to oscillate.
Who believed in 340BC that the earth was the centre of your solar system?
g
What is the force of gravitation between the earth and a body at the centre of earth?
The gravitational force between the earth and a body at the center of the earth would be 0 Newtons or 0 lbf. F=G (m1*m2)/r^2 r = zero if the center of the body is at the center of the earth
What is the effect of depth on the earth on the value of g?
As you move deeper into the Earth, the value of acceleration due to gravity (g) decreases slightly. This is because the mass directly below you is pulling you down, while the mass above you is also pulling you up. The net effect of these opposing forces is a slight decrease in the value of g as you move deeper into the Earth.
