Mars.
Kepler's third law states that the square of the orbital period of a planet is proportional to the cube of its semi-major axis. If a hypothetical planet is twice as far from the sun as Earth, its semi-major axis would be 2 times larger. Therefore, the period of this hypothetical planet would be √(2^3) = 2.83 times longer than Earth's period.
The orbital period of a planet can be calculated using Kepler's Third Law, which states that the square of the orbital period is directly proportional to the cube of the semi-major axis of the orbit. For a planet with twice the mass of Earth orbiting a star with the same mass as the Sun at a distance of 1AU (Earth-Sun distance), the orbital period would be the same as Earth's, which is about 365 days.
Mars
The moon closer to the planet would complete a revolution first, as it would need to cover a shorter distance in the same amount of time compared to the moon that is twice as far away. This is due to the fact that the closer moon has a smaller orbit and shorter path around the planet.
Mars has an orbital period of very approximately twice that of the earth
The planet that has a revolution period twice that of Earth is Mars. It takes Mars approximately 687 Earth days (or about 1.88 Earth years) to complete one orbit around the Sun.
Saturn has a period of revolution that is approximately twice as long as Earth's. While Earth takes about 365 days to complete one revolution around the Sun, Saturn takes roughly 29.5 Earth years to complete its orbit.
Mars.
Mars with an orbital period of 1.88 years.
Kepler's third law states that the square of the orbital period of a planet is proportional to the cube of its semi-major axis. If a hypothetical planet is twice as far from the sun as Earth, its semi-major axis would be 2 times larger. Therefore, the period of this hypothetical planet would be √(2^3) = 2.83 times longer than Earth's period.
No planet.
The orbital period of a planet can be calculated using Kepler's Third Law, which states that the square of the orbital period is directly proportional to the cube of the semi-major axis of the orbit. For a planet with twice the mass of Earth orbiting a star with the same mass as the Sun at a distance of 1AU (Earth-Sun distance), the orbital period would be the same as Earth's, which is about 365 days.
Mercury takes 88 Earth days to go around the Sun, but strangely, its day is twice as long taking 176 Earth days to rotate just once! Mercury's slow spin is evidence of why the planet has a magnetic field just 1% as strong as Earth's. (This may have been a very long answer)
Mars
Mercury completes an orbit of the Sun in 88 Earth days, which is about 3 months or 0.24 Earth years. The slowly spinning planet makes only 1.5 rotations per revolution, giving a sidereal day of 58.6 Earth days but a solar day, sunrise to sunrise, of 176 Earth days (twice as long as its year).
If the moon were to rotate twice during each revolution, the tides on the Earth would appear different. Also, the moon itself would show its far side rather than having the same side facing the planet all the time.