It depends on how much gravity that causes stars to form. It depends on how big the star in the galaxies is.
Yes, every planet and every star has gravity. In fact, every object that has mass, has gravity. Black holes have so much gravity that even light cannot escape.
A white dwarf is smaller, cooler, and denser than the star it evolved from. It is the remnant core of a star like our Sun after it has exhausted its nuclear fuel and collapsed under gravity.
The surface gravity of a white dwarf star with the mass of our Sun and the size of our Moon would be extremely high, much greater than what we experience on Earth. This is because gravity is directly proportional to the mass of the object. The intense gravity on the surface of such a white dwarf would crush any normal matter that comes into contact with it.
Gravity pulls the star in and tries to squeeze it down to a point. Because it pulls all of the atoms of the star in to the middle, gravity speeds them up, giving them energy. Eventually gravity gives enough energy to the atoms that they move fast enough that when they collide, they sometimes stick together and nuclear fusion happens. This is what gives a star its light and what keeps a star from collapsing further.
It depends on how much gravity that causes stars to form. It depends on how big the star in the galaxies is.
Yes, every planet and every star has gravity. In fact, every object that has mass, has gravity. Black holes have so much gravity that even light cannot escape.
the star's size
You're talking about a so-called "black hole". It doesn't necessarily have any more gravity than a normal star with the same mass has. It's just that if the mass is all crammed into a tiny space, then you can get much closer to it, and THAT's where the gravity is stronger.
Inside a star, the force of gravity is balanced by the pressure generated from nuclear fusion reactions occurring in the star's core. These nuclear reactions create an outward pressure that counteracts the force of gravity trying to collapse the star. This delicate balance between gravity and pressure determines the size, temperature, and lifespan of a star.
a black hole is your answer and it is because when a main sequenced star collects to much energy the gravity stops and forms a black hole
Yes. When a star dies for example, the inward gravitational pull is so dense that it creates a black hole!
Gravity depends on two things: the mass of the object you are dealing with. A more massive object has stronger gravity, and the close you get to the center without having any of the mass above you, the stronger the gravity gets. To start off, a neutron star has a very large mass, as much as 3 times the mass of the sun, compacted into a very small area, about the size of a city. Since it is in such a small area objects can get very close to the center of mass.
Gravity pushes and pulls on a star, balancing it out so it doesn't explode.
A star is a sphere of gas held together by its own gravity.
When the star's fuel source depletes and the nuclear reaction inside the star cannot resist the pull of gravity any more. The constant explosion in the star would want to expand but gravity of the star keeps it in the shape of a sphere. So when the fuel for the nuclear reaction has been used up, it will get pulled in by the force of gravity. To answer the question: it depends on what type of large star you are talking about, how much fuel it has, and how long it takes for that star to burn up its fuel.
Basically a black hole is a star, well a blue star most likely. A blue star will get bigger and explode in what's called a super nova. If there's still enough of the star left it will squash itself down into an atom! Pretty Small! A black hole pulls things in by gravity, when something gets smaller the more gravity it has so imagine how much gravity the squashed up star would have! So basically black holes do exist.