You mean the lug nuts? 80 foot pounds if you mean that. Most Hondas are 80 for the wheel torque
One foot-pound of torque is a force of one pound applied one foot from the object's axis of rotation.ANS 2 - pounds per foot and 'Torque' wrenches are very important in rebuilding many auto parts. -For instance, every bolt in a cylinder head must be very accurately torqued to a very particular specification. The torque wrench and knowledge of 'foot/pounds' allows you to do this.
If you mean the 3.4 liter LA1 engine, you should expect between 205 and 210 foot pounds of torque, and between 170 to 185 horsepower.
Torque is a twisting force applied to an object, like a wheel or a crankshaft. Note that motion is not required for torque to exist! If you stand on a lug wrench that is on a frozen lug bolt, you are applying a torque to that bolt even though there may be no movement. For our purposes, we will consider that torque is measured in pounds-force feet (lbf-ft) meaning the equivalent of a given force, in pounds, acting on the end of a lever of length in feet. For example, standing with 180 pounds body weight on a lug wrench one foot long yields 180 lbf-ft of torque. A child of 90 pounds standing on a two-foot lug wrench applies the same torque.
Foot Pounds of Energy
There are exactly 2148 pounds in 2148 pounds. And if you did not mean 2148 pounds you should have said as much in your question!
Torque is the amount of 'twist' that the engine produces in the shaft. Torque is measured as a force applied over a distance, so 1 pound force applied over a lever of 10 feet gives 10 lb ft, exactly the same torque as ten pounds applied over 1 foot. Suppose the piston produces a downward force of 100 pounds, and the throw of the crankshaft is 6", the torque is 100 x 0.5 = 50 lb ft. Obviously it varies over the cycle so the torque is usually quoted as the average taken over a few revolutions. Power is torque times rpm, and a gearbox will reduce the rpm but multiply the torque, so that the output torque times rpm is (nearly) equal to the input torque times rpm. At 5250 rpm the horse power in HP is equal to the torque in lb ft, so the general formula is that HP = torque (lb ft) x RPM/5250. In SI units, power (watts) = torque (Newton-metres) times angular speed (radians/sec).
No, 80 inch-pounds is not meant for finger tightening. It typically requires the use of a torque wrench set to the specific measurement to ensure proper tightening without damaging the object or component being worked on. It is important to follow manufacturer recommendations for torque specifications.
Metric fluid bolt spec? Exactly what does that mean? You want the torque specifications of a certain bolt. What bolt, used to attach what are you referring to?
Ft-Lbs is a measurement of torque. Torque is "twisting" force. Ft-Lbs is measured as follows: Imagine a 1 ft bar attached at some center point. The bar is horizontal and a 100 lb weight is attached to the bar at one foot from the center point. That would be the very definition of 100 ft-lb of torque. Of course for this to be accurate you'd have to account for the weight of the bar. In this instance 100 ft pounds of torque would mean that a 100 pound weight was used instead. You could also use a 100 ft bar and ONE pound weight, the theoretical results would be identical. Inch pounds are very similar, only the bar would be one inch long. To calculate 100 inch pounds you'd have a bar that was 1 inch long, at the horizontal and hang a 100 pound weight. For all practical purposes 100 inch pounds would be 1/12 of the torque represented by 100 Ft pounds. In other words, there are 12 inch lbs, in one ft. lb. An easy way to think of it is based on the unit of measure. Whether you are working with Ft-Lbs or In-Lbs or even in Metric using N-M (Newton-Meters) doesn't matter. If you were to express Ft-Lbs as "Pounds per Foot" or In-Lbs as "Pounds per Inch", or in metric "Newtons of force per Meter" it may be easier to understand. For conversion purposes, there are 12 inches in a foot, so "one foot pound" would equal "Twelve Inch Pounds". In other words, it takes "12 pounds of force on a one inch long bar" to equal the twisting force of "One pound of force on a one foot (12 inch) long bar"
If you mean the nuts holding the axle/bearing assembly, I believe they should be torqued to 230 foot-pounds, or one 160 pound person standing (not jumping) on the arm of the wrench 1.4375 feet from the center.
448