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How many grams of KI are in 25.0ml of a 3.0 (mv) KI solution?
To calculate the grams of KI in the solution, you need to first convert the 25.0 ml to grams using the density of the solution. Then, use the molarity (3.0 M) of KI to find the number of moles in the solution. Finally, use the molar mass of KI (166 g/mol) to convert moles to grams.
What is the molarity of 67.94 mL aqueous solution containing 2.822 g of KI?
To find the molarity, first calculate the number of moles of KI using its molar mass (166 g/mol). Then divide the moles of KI by the volume of the solution in liters (67.94 mL = 0.06794 L) to get the molarity. The molarity of the solution is approximately 6.24 M.
To 225 mL of a 0.80M solution of KI a student adds enough water to make 1.0 L of a more dilute KI solution What is the molarity of the new solution?
0.18M
What mass of KI is present in 276 mL of a 0.50 M solution?
To calculate the mass of KI in the solution, first calculate the number of moles of KI present using the formula moles = Molarity x Volume (in liters). Then, use the molar mass of KI (potassium iodide) to convert moles to grams. The molar mass of KI is 166 g/mol.
How many moles of KI are present in 500 ml of a 0.2M solution?
The answer is 0,1 mol.
What is the molarity of a solution prepared by dissolving 2.41 g of potassium iodide KI in 100 mL of water?
To calculate the molarity, you first need to convert the mass of KI to moles using its molar mass (166 g/mol). Then, divide the moles by the volume of solution in liters (0.1 L) to get the molarity. The molarity of the solution is approximately 1.45 M.
HOW TO prepare 0.1 n iodide solution in 500 ml water?
0.1 N iodide would be 0.1 moles of the iodide salt (e.g. KI) per liter of solution. For 500 ml, you would need 0.05 moles of the iodide salt. You need to state the salt (KI, NaI, LiI, etc.) in order to determine the actual mass required.
How Wagner react to alkaloid?
Dissolve 2.0 grams of iodine and 6.0 grams of KI in 100.0 ml of H2O.
How many mg per ml in a twenty percent solution?
A 20% solution would mean 20 g of the substance in 100 ml of solution. To convert this to mg per ml, you would have 20,000 mg of the substance in 100 ml of solution. Therefore, in a 20% solution, there would be 200 mg per ml.
How much acid is in 320 mL of a 15 percent acid solution?
There are 48 mL of acid in 320 mL of a 15% acid solution. This is calculated by multiplying the volume of the solution by the percentage of acid in the solution: 320 mL x 0.15 = 48 mL.
How do you prepare 40 ml of a 2 mg ml protein solution from a 10mg ml protein solution?
You can prepare a 2 mg/ml protein solution by diluting the 10 mg/ml protein solution with a diluent in a 1:5 ratio. Measure 8 ml of the 10 mg/ml protein solution and add 32 ml of the diluent to make a total volume of 40 ml. Mix properly to ensure uniform distribution of the protein in the solution.
What is the solubility of KI?
KI is highly soluble in water, with a solubility of approximately 31.6 g/100 mL at 25°C.
