In order to answer that, one would need to know what the circuit is designed to do (so that he would know how to tell when the circuit is "working"), and would also need to see the schematic diagram, in order to know exactly how the fixed resistor and the thermistor are configured in the circuit, and what other components are involved. Consider . . . If I came up to you on the street, or even for that matter in an Engineering lab, and I said to you "I've got a circuit with a coil and a resistor in it. Will it work if the impedance of the coil is greater than the resistance of the resistor ?", you would most certainly find yourself at a loss, just as I do when I read your question.
Often we want to easily change a resistor value, so we use a variable resistor. For example, we may want to change the resistor that controls the power sent to a LED, so we can easily make it brighter or dimmer. Often if we use a variable resistor, there is only a very narrow range that is useful. Continuing our example, sometimes we use several LEDs, and we use the variable resistor to set them all to the same brightness. In this case, the resistance range that sets the LED to be twice as bright as the the other LEDs, and the resistance range that sends so much power to the LED that it is permanently destroyed is even less useful. So we add a fixed resistor in series with the variable resistor -- the fixed resistor sets the minimum net resistance, no matter how we turn the knob on the variable resistor. In our example, the addition of the fixed resistor allows us to turn the variable resistor throughout its whole range, and the LED gets brighter and dimmer; without that resistor, a certain range of the knob on the variable resistor would allow so much power to go to the LED that it would be destroyed.
The resistance of a connecting wire that is less than the resistance of a resistor would depend on the materials and dimensions of the wire and resistor. Generally, most connecting wires have very low resistance compared to resistors. Copper wires, for example, have low resistance and are commonly used for connecting circuits.
The question is a bit ambiguous, but I will try to address it. If the 6 ohm resistance is in series with another resistance then some of the 5 volts would be dropped across the 6 ohm resistance and the remainder of the voltage would be dropped across the other resistance. To calculate the voltage, use the 'resistor voltage divider equation' (Google it). If the 5 volts is applied across only a 6 ohm resistance, then the top of the resistor is at 5 volts and the bottom of the resistor would be at 0 volts. The resistor would drop all of the voltage.
The total resistance would be 40 ohm.
Because by increasing the load resistance, the total circuit resistance is reduced. This means with less resistance, there is more current drawn from the source. Doubling the size of a load resistor increases the load current.
No. The resistance in a series circuit is all the resistor values added together. eg. If two resistors were in a circuit, one was 10 ohms and the other was 30 ohms, the resistance in the circuit would be 30 ohms. Hope this helps!
It depends on what you want to accomplish. If you want to decrease the resistance in a circuit, you would place the box in parallel to some other resistor. If you want to increase the resistance in a circuit, you would place the box in series.
The old resistor was burned out. If you burn out the new one again, replace the blower motor.
a) fixed variable b) variable resistance c) body weight resistance
I believe in that case, it would normally let no current pass. If that happens, the resistance indicator will show a very high resistance value, since resistance is defined as voltage divided by current. This is often called something like "infinite resistance".
To find the current running through the 40 ohm resistor in parallel with the 120 ohm resistor, first calculate the total resistance of the circuit using the formula 1/RT = 1/R1 + 1/R2, where R1 = 120 ohms and R2 = 40 ohms. Once you have the total resistance, you can use Ohm's Law (I = V/R) to find the current flowing through the 40 ohm resistor by dividing the total voltage (120V) by the total resistance.