Under to black rubber caps on the very top of the engine. Remove the black caps and the plugs are reset about 4 inches down.
sixteen liters
A person can get a wire diagram for this car in its maintenance or repair manual. A diagram may also be obtained from an auto part store, if the local one will print the diagram.
from what I've been told you have to get to it from the top removing the air intake and the exhaust manifold
Yes
16l/100kms :( city 10l/100kms :I Highway
find the fan belt, make sure the car is OFF, then take a regular bar of soap and rub it on the underside of fan belt. That will stop it from squealing. Worked for me! look if is a car or sedan have to be a transversal engine and dont have fan belt if has only one belt they call it serpentine belt and is too old got to go replace it if it has two belts one for alternator and ac compressor and one for power steering that means the one for the alternator is loose and can be tight the noise is too loud with the heater on because the alternator is working extra and the belt is slipping
There are several things to check for. Check the battery terminals. And there should be a wire from the positive terminal (+) directly to the alternator. There can be a fusible link. A fusible link is kind a fuse embebeded into the wire, in some point the wire gets thick. If you have no electricity in the car check the main big fuses, and fusible links. Check the fuses under the hood and under the dash. You may have a blown fuse. Hope this helps.
If you are facing the motor, it is on the right side, under the plastic housing. To replace the timing belt,you will need to remove the valve cover, remove a/c belt and PS belt. The motor mount will also need to be disconnected and the motor raised slightly.
on the highway doing 100km/h i get 16l/100k. i have a 02, about 7000lbs with ladders on the roof.
you can't unless you have the computer to plug in the diagnosis port...it's all controled via the ecm!!!
12 and 4. Either one can be the length, the other is the width. To solve algebraically: 2L + 2W = 32 L x W = 48 substitute the L value for W (W = 16-L) L (16-L) = 48 -L2 +16L -48 = 0 L2 -16L + 48 = 0 (L-12)(L-4) = 0