7
the one between 6 :clock and 9 o:clock.
The graph of -5w + 9 = 14 is the single point w = -1.
Y = 2/3X - 3 you know Y, 0 out Y to find X intercept 2/3X - 3 = 0 2/3X = 3 X = 9/2 a line between Y = -3 and X = 9/2 comes from the 3rd quadrant, through the 4th quadrant and into the first
-9/4 or -2.25
7
A vertical line intercepting the x-axis at 9 with an undefined slope.
the one between 6 :clock and 9 o:clock.
It's the equation of a straight-line graph. Every point on the line is a solution of the equation. There are an infinite number of them.
The graph is a straight line. It crosses the y-axis at y=-9/7 , and its slope is 1426/7 .
The graph shifts downward (negative y) by 9 units.
-9
x=9
9
Since 'x' and 'y' both appear to the first power, this is a linear equation.That means that the graph is a straight line, and it doesn't 'open'.The line has a slope of -1, and it cuts the y-axis at y=9.
Divide the graph into 4 parts and each part is a quadrant. Traditionally, we use the x and y axis to divide it. The portion of the graph with positive x and y coordinates is the first quadrant, The second has positive y values and negative x values, while the third quadrant has both negative x and negative y values. The last is the fourth quadrants which is below the first quadrant. It has positive x values and negative y values. If you made the origin, the point (0,0) the center of a clock, the first quadrant is between 3 and 12 and the second between 12 and 9, the third between 9 and 6 and the fourth between 12 and 3.
The line y = x will shift up when you add a value to x and shift down when you subtract a value from x.