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yes it is divisible by 3, 9, 37, and 111
Yes, The quotient is 37.
Because nine goes into 333 evenly; 37 times.
3 and 333 **************** I would like to add 1 and also 9 (999 ÷ 9 = 111) to the above list.
Yes, the result is 333.
1, 3, 9, 37, 111, 333
yes it is divisible by 3, 9, 37, and 111
Out of that list, 3 and 9.
Yes, The quotient is 37.
Because nine goes into 333 evenly; 37 times.
3 and 333 **************** I would like to add 1 and also 9 (999 ÷ 9 = 111) to the above list.
Yes, the result is 333.
1998 is an even number, so it's divisible by 2; 1998/2 = 999. If you add up the numbers of that result, 9 + 9 + 9, you get 27. Since 27 is divisible by 3, 999 must also be divisible by 3; 999/3 = 333. Once again, if you add up the numbers of that result, 3 + 3 + 3, you get 9, and since 9 is divisible by 3, 333 must be too; 333/3 = 111. Again, if you add up the numbers of that result, 1 + 1 + 1, you get 3, so 111 must also be divisible by 3; 111/3 = 37. Our factors are now 2 X 3 X 3 X 3 X 37, which are all prime numbers. Thus, the prime factorization of 1998 is 2 X 33 X 37.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
37
9 is divisible by both 3 and 9
171, 252, 333, 414, 585, 666, 747, 828, 909, 999