if there is no integer answer, they are irrational
ex. sq root 5 is irrational but sq root 9 = 3 so it is rational,integer, counting number
if you are taking sq root of a negative they are imaginary ex. sqroot (-9)
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The square roots of all positive real numbers are real numbers.
The square roots of all negative real numbers are imaginary numbers.
Some square roots are rational, but the vast majority are irrational.
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Only a set can have subsets, a number such as -2.38 cannot have subsets.
The number 1.68 belongs to the subsets of real numbers known as rational numbers and decimal numbers. As a rational number, 1.68 can be expressed as the ratio of two integers (84/50). It is also a decimal number, specifically a terminating decimal, where the digits after the decimal point eventually end.
There are infinitely many subsets of real numbers. For example, {2, sqrt(27), -9.37} is one subset.
The rational numbers are a subset of the real numbers. You might recall that rational numbers are those that can be expressed as the ratio of two whole numbers (no matter how large they are). Irrational numbers, like pi, cannot. But both sets (the rational and irrational numbers) are subsets of the real numbers. In fact, when we look at all the numbers, we are looking at the complex number system. We break that down into the real and the imaginary numbers. And the real numbers have the rational and irrational numbers as subsets. It's just that simple.
An irrational number is a number that can't be expressed by a fraction having integers in both its numerator and denominator. A rational number can be.